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mylen [45]
2 years ago
10

Janie receives an allowance of $ 3 $3dollar sign, 3 per week. In addition, she can earn $ 2 $2dollar sign, 2 for each chore she

does. This week, she wants to earn enough money to buy a CD for $ 1 3 $13dollar sign, 13. Janie can do fractions of chores. Write an inequality to determine the number of chores, c cc, Janie must do this week to earn enough money to buy a CD.
Mathematics
1 answer:
Gnesinka [82]2 years ago
6 0

Hello  Dafnemlp47vj7

The inequality for one week would be <u><em>13  = 2c + 3 </em></u>

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one maid can clean the house three times faster than another. Working together they can clean the entire house in 3 hours. How l
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<span>Faster maid DATA:
time = x hr/job ; rate = 1/x job/jhr
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time = 3x hr/job ; rate = 1/3x job/hr
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7 0
3 years ago
Can some body help me?
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24

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3 0
2 years ago
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A lake contains 4 distinct types of fish. Suppose that each fish caught is equally likely to be any one of these types. Let Y de
gregori [183]

a= μ-3.16*σ , b= μ+3.16*σ if each fish caught is equally likely to be any one of these 4 distinct types.

<h3>What is meant by Chebyshev inequality?</h3>

Chebyshev's inequality is a probability theory that ensures that, over a vast range of probability distributions, no more than a particular proportion of values would be present within a selected limits or range as from mean. In other words, only a certain fish caught will be discovered within a given range of the distribution's mean.

The formula for which no more than a particular number of values can exceed is 1/K2; in other words, 1/K2 of a distribution's values can be more than or equal to K standard deviations away from the distribution's mean. Furthermore, it asserts that 1-(1/K2) of a distribution's values must be within, but not include, K standard deviations of the distribution's mean.

How to solve?

from Chebyshev's inequality for Y

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

where

Y =  the number of fish that need be caught to obtain at least one of each type

μ = expected value of Y

σ = standard deviation of Y

P(| Y - μ|≤ k*σ ) = probability that Y is within k standard deviations from the mean

k= parameter

thus for

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

P{a≤Y≤b} ≥ 0.90 →  1-1/k² = 0.90 → k = 3.16

then

P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90

using one-sided Chebyshev inequality (Cantelli's inequality)

P(Y- μ≥ λ) ≥ 1- σ²/(σ²+λ²)

P{Y≥b} ≥ 0.90  →  1- σ²/(σ²+λ²)=  1- 1/(1+(λ/σ)²)=0.90 → 3= λ/σ → λ= 3*σ

then for

P(Y≥ μ+3*σ ) ≥ 0.90

In order to learn more about Chebyshev inequality, visit:

brainly.com/question/24971067

#SPJ4

4 0
1 year ago
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