60 /1 = 120 /2 = 180 /3
hope it helps
Answer:
∠ EFH = 112°
Step-by-step explanation:
∠ ACD and ∠ EFH are Alternate exterior angles and are congruent, thus
11x - 20 = 9x + 4 ( subtract 9x from both sides )
2x - 20 = 4 ( add 20 to both sides )
2x = 24 ( divide both sides by 2 )
x = 12
Thus
∠ EFH = 11x - 20 = 11(12) - 20 = 132 - 20 = 112°
Answer:
Step-by-step explanation:
you can think in a reverse way:
Take
![3x(x^2+2x+3y^2)= 3x^3+6x^2+9xy^2.](https://tex.z-dn.net/?f=3x%28x%5E2%2B2x%2B3y%5E2%29%3D%203x%5E3%2B6x%5E2%2B9xy%5E2.)
So the answer is
![3x^3+6x^2+9xy^2 = 3x(x^2+2x+3y^2)](https://tex.z-dn.net/?f=3x%5E3%2B6x%5E2%2B9xy%5E2%20%3D%203x%28x%5E2%2B2x%2B3y%5E2%29)
Answer:
14
Step-by-step explanation:
In a triangle, the midline joining the midpoints of two sides is parallel to the third side and half as long, so
FB = EC/2
2x - 6 = 44/2
2x - 6 = 22
2x = 22 + 6
2x = 28
x = 28/2
x = 14
<span>Circle D circumscribes ABC and ABE, The statements that best describe the triangles are:
</span><span>Statement I: The perpendicular bisectors of ABC intersect at the same point as those of ABE.
Statement II: The distance from C to D is the same as the distance from D to E. Hence, each of them (CD and DE) is a radius of the given circle.
So, the answer is the second option, I and II.
</span>