Through: (1,-5), perpendicular to y=18x+26
1 answer:
Answer:
Step-by-step explanation:
If you're asking for the equation of a line that goes through (1,-5) and is perpendicular to y=18x+26 here's what you do.
1. find the slope of the new line by taking the negative reciprocal of the slope of the first line ()
2. plug in the point (1,-5) and the new slope into the point slope form equation
3.Now that you have y-(-5)= -1/18(x-1) simplify
3.a y-(-5)= -1/18x + 1/18
3.b y=-1/18x - 89/18
4. final equation you get is y = -1/18 - 89/18
You might be interested in
The difference between the maximum value of g(x) and the minimum value of f(x) is 5.
Given function is:
......(1)
The general form of a quadratic equation is with
.
As we know the minimum value of a quadratic function is when a>0
For f(x) a>0 so minimum value of f(x) = =7
From the graph, the maximum value of g(x) =12
So, the difference between the maximum value of g(x) and the minimum value of f(x) =12-7 =5
Hence, the difference between the maximum value of g(x) and the minimum value of f(x) is 5.
To get more about quadratic functions visit: