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Digiron [165]
4 years ago
7

How can triangles be different

Mathematics
2 answers:
notka56 [123]4 years ago
7 0
They can be different because one side of the triangle may be a different length than anothor side
r-ruslan [8.4K]4 years ago
7 0
Triangles can be different if they are a right triangle with a right angle, a acute triangle with acute angles, or a obtuse triangle with on obtuse angle. Triangles can also be different based of off side length all sides are the same length, 2 sides are the same length, or no sides are the same length.
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The length of a rectangle is 7 inches longer than it is wide. If the area is 44 square inches, what are the dimensions of the re
MatroZZZ [7]
Area = *Longer Side* x *Shorter side*

44 = (x + 7) * x
44 = x^2 + 7x
0 = x^2 + 7x - 44
0 = (x + 11)(x - 4)
0 = x + 11 OR 0 = x - 4
x = -11*impossible* OR x = 4
So x = 4
8 0
3 years ago
Please help, tysm for your assistance if you do :)
Katyanochek1 [597]

Answer:

27/49

plz mark me as brainliest

5 0
3 years ago
Jim changes his passwords every 90 days and cleans out his files every 50 days. If he just did both on the same day, what is the
Naily [24]

Answer:

The Answer To This Question

is 490.

Step-by-step explanation:

I already answered it.

But seeing as no one else will. Please forgive me

6 0
3 years ago
OUT OF 32 STUDENTS IN A CLASS, 5 SAID THEY RIDE THEIR BIKES TO SCHOOL.  BASED ON THESE RESULTS, HOW MANY OF THE 800 STUDENTS IN
svet-max [94.6K]
Let, the total number of students in school that ride the bike to school be "x"
Now,
Using ratio and proportion, we get,
\frac{5}{32} = \frac{x}{800}

\frac{5}{32}*800 = \frac{x}{800} *800

\frac{4000}{32} =x

125 =x

x=125

So, out of 800 students, 125 ride their bike to school.


4 0
3 years ago
Write an equation in slop _intercept form of the line that bisects the angle formed by BA and BC
kotegsom [21]

Answer:

y = -x + 2

Step-by-step explanation:

Angle between these lines = 90°

Angle between BC and the angle bisector BD = 45°

Since, m(∠DBE) = 90° + 45° = 135°

Therefore, slope of the angle bisector BD = tan(90° + 45°)

                                                                      = -tan(45)°

                                                                      = -1

Let the equation of the angle bisector which passes through (x', y') and slope = m,

y - y' = m(x - x')

Where m = slope of the line = (-1)

Since, the angle bisector passes through a point B(-1, 3),

Equation of BD will be,

y - 3 = (-1)(x + 1)

y - 3 = -x - 1

y = -x - 1 + 3

y = -x + 2

8 0
3 years ago
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