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Alenkinab [10]
3 years ago
11

Find the domain and range of radical function

Mathematics
1 answer:
Tju [1.3M]3 years ago
8 0

The radical function is 3√x + 1.

Since the cubic root of zero is zero, 0 would be x.

Add zero and one, which gives you 1. 1 is y.

You get (0,1)

Since this is a positive radical, it would be going to the top right.

So, the domain is x ≥ 0

the range is y ≥ 1

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∠1 ​ and ∠2 are supplementary. ∠1=124°∠2=(2x+4)° Select from the drop down menu to correctly answer the question.
Alex_Xolod [135]
Remark
Supplementary angles add up to 180o. 

Givens
<1 = 124
<2 = 2x + 4

I imagine you are looking for either x or <2. 

Equation
<1 + <2 = 180          Substitute the givens
124 + 2x + 4 = 180  Collect like terms on the left.
128 + 2x = 180         Subtract 128 from both sides
2x = 180 - 128          Collect like terms on the right   
2x = 52                     divide by 2
x = 52/2
x = 26 <<<<<<<<< answer

<1 = 124
<2 = 2x + 4 = 2*26 + 4
<2 = 52 + 4
<2 = 56  <<<<<<<< answer

We need choices if you want an exact answer.

3 0
3 years ago
The cuboid has volume 288cm^3 (a) the cuboid has a length 12 cm and a width 5cm Calculate the height of the cuboid (b) 1cm^3 of
klemol [59]

Answer:

height= 4.8cm

Step-by-step explanation:

volume= length×width× height given the volume and length and width, 288=12×5×h

288=60h

divide both sides by 60

h=4.8cm

7 0
3 years ago
Read 2 more answers
Please help me with this math question!
barxatty [35]
1) Change radical forms to fractional exponents using the rule:
The n<span>th root of "</span>a number" = "that number" raised to the<span> reciprocal of n.
For example </span>\sqrt[n]{3} =   3^{ \frac{1}{n} }.

The square root of 3 (\sqrt{3}) = 3 to the one-half power (3^{ \frac{1}{2} }).
The 5th root of 3 (\sqrt[5]{3}) = 3 to the one-fifth power (3^{ \frac{1}{5} }).

2) Now use the product of powers exponent rule to simplify:
This rule says a^{m} a^{n} = a^{m+n}&#10;. When two expressions with the same base (a, in this example) are multiplied, you can add their exponents while keeping the same base.

You now have (3^{ \frac{1}{2} })*(3^{ \frac{1}{5} }). These two expressions have the same base, 3. That means you can add their exponents:
(3^{ \frac{1}{2} })(3^{ \frac{1}{5} })\\&#10;= 3^{(\frac{1}{2} + \frac{1}{5}) }\\&#10;= 3^{\frac{7}{10}}

3) You can leave it in the form 3^{\frac{7}{10}} or change it back into a radical \sqrt[10]{3^7}

------

Answer: 3^{\frac{7}{10}} or \sqrt[10]{3^7}
6 0
3 years ago
What is the factorization of 729^15+1000​
Nesterboy [21]

\bf \textit{difference and sum of cubes} \\\\ a^3+b^3 = (a+b)(a^2-ab+b^2) \\\\ a^3-b^3 = (a-b)(a^2+ab+b^2) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} 729=27^2\\ \qquad (3^3)^2\\ 1000=10^3 \end{cases}\implies 729^{15}+1000\implies ((3^3)^2)^{15}+10^3 \\\\\\ ((3^2)^{15})^3+10^3\implies (3^{30})^3+10^3\implies (3^{30}+10)~~[(3^{30})^2-(3^{30})(10)+10^2] \\\\\\ (3^{30})^3+10^3\implies (3^{30}+10)~~~~[(3^{60})-(3^{30})(10)+10^2]

now, we could expand them, but there's no need, since it's just factoring.

3 0
3 years ago
Plz help quick in the question in the pic
yaroslaw [1]

Answer:

The number is 92

Step-by-step explanation:

Let x equal the number

It is tripled

3x

Then it is tripled again

3(3x)

That equals 828

3(3x) = 828

9x =828

Divide each side by 9

9x/9 =828/9

x =92

8 0
3 years ago
Read 2 more answers
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