Assuming these are 4^(1/7), 4^(7/2), 7^(1/4) and 7^(1/2), the conversion process is pretty quick. the denominator, or bottom, of your fraction exponent becomes the "index" of your radical -- in ∛, "3" is your index, just for reference. the numerator, aka the top of the fraction exponent, becomes a power inside the radical.
4^(1/7) would become ⁷√4 .... the bottom of the fraction becomes the small number included in the radical and the 4 goes beneath the radical
in cases such as this one, where 1 is on top of the fraction radical, that number does technically go with the 4 beneath the radical--however, 4¹ = 4 itself, so there is no need to write the implied exponent.
4^(7/2) would become √(4⁷) ... the 7th power goes with the number under your radical and the "2" becomes a square root
7^(1/4) would become ⁴√7 ... like the first answer, the bottom of the fraction exponent becomes the index of the radical and 7 goes beneath the radical. again, the 1 exponent goes with the 7 beneath the radical, but 7¹ = 7
7^(1/2) would become, simply, √7
Answer: <u><em>The building is 35 meters tall.</em></u>
Step-by-step explanation:
<em>420 </em><u><em>divided by </em></u><em>24 is 17.5 </em>
<em>17.5 </em><u><em>x </em></u><em>2 is 35 </em>
<em>(im multiplying by two because it says that a person who is 2 meters tall casts a shadow that is 24 meters long. ***)</em>
<em />
Answer:
when x=6, y=30
when x=7.5, y=37.5
Step-by-step explanation:
Just plug in the value of x into the equation y=5x
so when x=6, the equation will be y=5(6). In this case y=30
when x =7.5, the equation will be y=5(7.5). So y=37.5
Answer:
The positive numbers are 51 and 53
Step-by-step explanation:
Let first odd integer be x and another odd integer is (x+2).
According to the given condition,
The product of two positive consecutive odd integers is 2703 i.e.
x(x+2) = 2703
It is a quadratic equation. It can be solved as follows :
x = 51 and x = -53
Neglecting negative sign,
The first number = 51
Another number =(51+2) = 53
Hence, the positive numbers are 51 and 53.
