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4 years ago

Can anyone PLZ help???? Attached jpeg

Mathematics

1 answer:

yarga [219]4 years ago

8 0

Domain- all the x-values that can be plugged into the function/ applicable to the function.

x-values in this case are measured in units of time(years) AFTER he deposited the amount.

Therefore, we only have positive x-values because the yearly interest rate in this function is only applicable to a positive number of years.
The bracket means including zero
The parentheses mean not including zero.
Whenever the infinity symbol(∞) is used it is always accompanied by a parentheses.

[0, ∞) is the answer because infinitely many positive number of years can be plugged into this function.

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Let us suppose we have data on the absorbency of paper towels that were produced by two different manufacturing processes. From

maksim [4K]

Answer:

The 95% CI for the difference of means is:

$-155.45 \leq \mu_1-\mu_2 \leq -44.55$

Step-by-step explanation:

The question is incomplete:

"Find a 95% confidence interval on the difference of the towels mean absorbency produced by the two processes. Assumed that the standard deviations are estimated from the data. Round to two decimals places."

Process 1:

- Sample size: 10

- Mean: 200

- S.D.: 15

Process 2:

- Sample size: 4

- Mean: 300

- S.D.: 50

The difference of the sample means is:

$M_d=M_1-M_2=200-300=-100$

The standard deviation can be estimated as:

$\sigma_d=\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}\\\\\sigma_d=\sqrt{\frac{15^2}{10}+\frac{50^2}{4}} =\sqrt{22.5+625}=\sqrt{647.5}=25.45$

The degrees of freedom are:

$df=n_1+n_2-2=10+4-2=12$

The t-value for a 95% confidence interval and 12 degrees of freedom is t=±2.179.

Then, the confidence interval can be written as:

$M_d-t\cdot \sigma_d\leq \mu_1-\mu_2 \leq M_d+t\cdot \sigma_d\\\\-100-2.179*25.45\leq \mu_1-\mu_2 \leq -100+2.179*25.45\\\\-100-55.45 \leq \mu_1-\mu_2 \leq -100+55.45\\\\ -155.45 \leq \mu_1-\mu_2 \leq -44.55$

8 0

3 years ago

In order to remove water from a flooded basement, two pumps, each rated at 40 gallons per minute, are used. After half an hour,

Scrat [10]

Answer:

3600 gallons of water was removed from the basement.

Step-by-step explanation:

Given:

Rate of each pump = 40 gallons/min

We need to find find the number of gallons of water removed from the basement.

Solution:

Now Given:

After half an hour, the one pump burns out.

Now we know that;

1 hour = 60 mins

$\frac12$ hour = $\frac{60}{2}=30\ mins$

Now for 30 mins both the pumps were working and removing the water.

So we can say that;

Water remove for first 30 mins = $40\times2\times30=2400\ gallons$

Also Given:

the second pump finishes removing the water half an hour later.

So we can say that;

Water removed for next 30 mins = $40\times 30\times1 =1200\ gallons$

Now we can say that;

Total water removed from the basement is equal to sum of Water remove for first 30 mins and Water removed for next 30 mins .

framing in equation form we get;

Total water removed from the basement = $2400+1200=3600\ gallons.$

Hence 3600 gallons of water was removed from the basement.

6 0

3 years ago

You and your friend each deposit $50 in separate savings accounts. Your account earns 2% simple annual interest. Your friend’s a

d1i1m1o1n [39]

Answer:

I am will take 20 years to get 20$

My friend will take 10 years to get 20$

Step-by-step explanation:

$Let \: the \: no. \: of \: years : x \\ \\ for \: me \\ x \times (50 \times 2\%) = 20 \\ x \times 1 = 20 \\ x = 20 years\\ for \: my \: friend \\ x \times (50 \times 0.04) = 20 \\ 2x = 20 \\ x = 10 \: years$