<h3>3
Answers: Choice D, Choice E, Choice F</h3>
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Explanation:
The inequality 6x - 10y ≥ 9 solves to y ≤ (3/5)x - 9/10 when you isolate y.
Graph the line y = (3/5)x - 9/10 and make this a solid line. The boundary line is solid due to the "or equal to" as part of the inequality sign. We shade below the boundary line because of the "less than" after we isolated for y.
Now graph all of the points given as I've done so in the diagram below. The points in the blue shaded region, or on the boundary line, are part of the solution set. Those points are D, E and F.
We can verify this algebraically. For instance, if we weren't sure point E was a solution or not, we would plug the coordinates into the inequality to get...
6x - 10y ≥ 9
6(5) - 10(2) ≥ 9 .... plug in (x,y) = (5,2)
30 - 20 ≥ 9
10 ≥ 9 ... this is a true statement
Since we end up with a true statement, this verifies point E is one of the solutions. I'll let you check points D and F.
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I'll show an example of something that doesn't work. Let's pick on point A.
We'll plug in (x,y) = (-1,1)
6x - 10y ≥ 9
6(-1) - 10(1) ≥ 9
-6 - 10 ≥ 9
-16 ≥ 9
The last inequality is false because -16 is smaller than 9. So this shows point A is not a solution. Choices B and C are non-solutions for similar reasons.
The common ratio of the given geometric sequence is the number that is multiplied to the first term in order to get the second term. Consequently, this is also the number multiplied to the second term to get the third term. This cycle goes on and on until a certain term is acquired. In this item, the common ratio r is,
r = t⁵/t⁸ = t²/t⁵
The answer, r = t⁻³.
The next three terms are,
n₄ = (t²)(t⁻³) = t⁻¹
n₅ = (t⁻¹)(t⁻³) = t⁻⁴
n₆ = (t⁻⁴)(t⁻³) = t⁻⁷
The answers for the next three terms are as reflected above as n₄, n₅, and n₆, respectively.
Answer:
1/4
Step-by-step explanation:
1/2 × 2/3
= 1×3 = 1
2×2 = 4
Therefore,
1/2 × 2/3 = 1/4//
Answer: Michael is 72.
hope this helps
Step-by-step explanation:
Let Brandon be b. Then Michael is 3g.
3g-18=9(b-18)
3g-18=9g-162
6g=144
b=24
3g=72
For any arbitrary 2x2 matrices

and

, only one choice of

exists to satisfy

, which is the identity matrix.
There is no other matrix that would work unless we place some more restrictions on

. One such restriction would be to ensure that

is not singular, or its determinant is non-zero. Then this matrix has an inverse, and taking

we'd get equality.