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Ahat [919]
4 years ago
9

I need help with these 3 questions . these questions were the ones i got confused on.

Mathematics
1 answer:
olga55 [171]4 years ago
7 0

1) AB + BC = AC. Plug in for each of these, you get:

x - 3 + 7x + 12 = 6x + 23

Combine like terms:

8x + 15 = 6x + 23

Subtract 6x from both sides and subtract 15 from both sides so you get variables on one side and constants on the other.

8x - 6x = 23 - 15

2x = 8

Divide both sides by 2 to isolate the variable.

x = 8/2 = 4

x = 4.

2) Same thing to start out. AB + BC = AC.

2y + 5 + 3y - 4 = 7y - 5

Combine like terms:

5y + 1 = 7y - 5

Subtract 5y from both sides and add 5 to both sides so that you get variables on one side and constants on the other.

1 + 5 = 7y - 5y

6 = 2y

Divide both sides by 2 to isolate the variable.

y = 6/2 = 3

y = 3.

Now we must plug in our y-value. If AB = BC, then point is the mid-point.

2y + 5 = 3y - 4

2(3) + 5 = 3(3) - 4

6 + 5 = 9 - 4

11 ≠ 5

Point B is not the midpoint.

3) AH + HS = AS

5b - 1 + 12b + 7 = 8b + 9

Combine like terms:

17b + 6 = 8b + 9

Subtract 8b from both sides and 6 from both sides to get variables on one side and constants on the other:

17b - 8b = 9 - 6

9b = 3

Divide by 9 on both sides to isolate the variable:

b = 3/9 = 1/3.

Now, we have to find AS. So plug in your b-value into the AS equation.

AS = 8b + 9

8(1/3) + 9

8/3 + 9 -> 8/3 + 27/3 = 35/3 = 11 and 2/3

AS = 11 and 2/3 units

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h(-3) - h( - 2) = -  \frac{5}{  8} \\ \\

Step-by-step explanation:

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h( - 3) =  \frac{2 {( - 3)}^{2}  - ( - 3) + 1}{3( - 3) - 2} \\ h( - 3) =  \frac{2 (9) + 3 + 1}{ - 9- 2} \\ h( - 3) =  \frac{18 + 4}{ - 11} \\ h( - 3) =    \frac{22}{  - 11} \\ h(-3) = -2

h( - 2) =  \frac{2 {( - 2)}^{2}  - ( - 2) + 1}{3( - 2) - 2} \\ h( - 2) =  \frac{2 (4)  +  2+ 1}{- 6 - 2} \\ h( - 2) =  \frac{8 +  3}{- 8} \\ h( - 2) =  \frac{11}{- 8}

h(3) - h( - 2) = -2 - \frac{11}{- 8} \\ h(3) - h( - 2) =-2 + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-2}{1}+ \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16}{8} + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16+11}{8} \\ h(3) - h( - 2) = \frac{-5}{8} \\ - \frac{5}{ 8}

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<h2>Question:</h2>

find simple interest

Rs.6500 for 2years 3months at

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<h2>Solution :</h2>

To find the simple interest , We'd use the following formula:-

<h2>P×R×T/100</h2>
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.°.

S.I = 65×13.5

S.I = Rs.877.50

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