Let the five terms be: a, a + d, a + 2d, a + 3d, a + 4d, then
a + a + d + a + 2d + a + 3d + a + 4d = 5a + 15d = 40
i.e. a + 3d = 8
Also, (a + 2d)(a + 3d)(a + 4d) = 224
(a + 3d - d)(a + 3d)(a + 3d + d) = 224
(8 - d)(8)(8 + d) = 224
(8 - d)(8 + d) = 224/8 = 28
64 - d^2 = 28
d^2 = 64 - 28 = 36
d = sqrt(36) = 6
But a + 3d = 8
a + 3(6) = 8
a = 8 - 18 = -10
Therefore, the term of the sequence is: -10, -10 + 6, -10 + 2(6), -10 + 3(6), -10 + 4(6)
= -10, -4, -10 + 12, -10 + 18, -10 + 24
= -10, -4, 2, 8, 14
Answer:
{7x^2+168x+840}/{x+12}
Step-by-step explanation:
Answer:
see attachment
Step-by-step explanation:
Answer:
Graph A → y=√x.
Graph B → y=(√x) - 1.
Graph C → y=√(x-1).
Graph D → y= -√x.
Graph E → y= -√(x-1)
Step-by-step explanation:
The graph 'A' intercepts the y-axis at (0, 0). Therefore it belongs to the function y=√x.
The graph 'D' is exactly the same graph 'A' but reflected across the x-axis. Therefore, it belongs to the function y=-√x.
The function 'C' is exactly the same function y=√x but translated one unit to the right, therefore, the solution function is y=√(x-1)
The graph 'E' is exactly the same graph 'C' but reflected across the x-axis, therefore the function is: y= -√(x-1)
In the options you have two times the function y=√x. I assume that's a mistake. The graph 'B' corresponds to y = (√x) - 1