Find all the zeros of x^3-5x^2-x+5
1 answer:
The fact that the coefficients are pairwise identical (except for sign) tells you that x^2 -1 is a factor (and x-5 is the other factor). Of course, you recognize x^2-1 as a special form (the difference of squares) that is factored as (x +1)(x -1).
The zeros are x = -1, +1, +5.
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A graphing calculator confirms this.
The zeros are x = -1, +1, +5.
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A graphing calculator confirms this.
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Answer:
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Step-by-step explanation:
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<u>Step-by-step explanation:</u>
varies directly means:
Step 1: solve for k ⇒
Step 2: plug in the given value and k to solve for the missing value:
42(5) = 21(x)
2(5) = x
10 = x