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emmasim [6.3K]
3 years ago
13

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

e given equation. Using this equation, find the maximum height reached by the rocket (write out the full number). y=-16x^2+147x+118 The Maximum Height reached by the rocket is _____ feet.
Mathematics
1 answer:
Alexus [3.1K]3 years ago
6 0

Answer:

The Maximum Height reached by the rocket is 456.1 feet

Step-by-step explanation:

In order to calculate the maximum height reached by the rocket we would have to calculate first the derivative of y=-16x^2+147x+118 as follows:

derivative of y=-16x^2+147x+118=y'=dy/dx=d/dx(-16x^2+147x+118)

y'=-32x+147

Therefore, x=147/32

x=4.59375

Therefore, the maximum height reached by the rocket=-16*4.59375^2 + 147*4.59375 + 118

The maximum height reached by the rocket=456.1

The Maximum Height reached by the rocket is 456.1 feet

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Answer: a) x = 5 or -1 b) x = √3+2

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a) (x − 2)² = 9

First step is to take the square root of both sides to eliminate the square

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4 0
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