Question

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the maximum height reached by the rocket (write out the full number). y=-16x^2+147x+118 The Maximum Height reached by the rocket is _____ feet.

Answer 1

Answer:

The Maximum Height reached by the rocket is 456.1 feet

Step-by-step explanation:

In order to calculate the maximum height reached by the rocket we would have to calculate first the derivative of y=-16x^2+147x+118 as follows:

derivative of y=-16x^2+147x+118=y'=dy/dx=d/dx(-16x^2+147x+118)

y'=-32x+147

Therefore, x=147/32

x=4.59375

Therefore, the maximum height reached by the rocket=-16*4.59375^2 + 147*4.59375 + 118

The maximum height reached by the rocket=456.1

The Maximum Height reached by the rocket is 456.1 feet