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IrinaVladis [17]
3 years ago
6

HELP!!!!

Mathematics
1 answer:
ch4aika [34]3 years ago
8 0

Answer:

8 y^{50}

Step-by-step explanation:

Given (64 y Superscript 100 Baseline) Superscript one-half.

Let us write it into an equation.

\left(64 y^{100}\right)^{\frac{1}{2}}

Apply radical rule: \sqrt[n]{a}=a^{\frac{1}{2}} and a^{m+n}=a^m+a^n

\begin{aligned}\left(64 y^{100}\right)^{\frac{1}{2}} &=\sqrt[2]{64 y^{100}} \\&=\sqrt[2]{8^{2} y^{50} y^{50}} \\&=\sqrt[2]{8^{2}\left(y^{50}\right)^{2}} \\&=8 y^{50}\end{aligned}

Hence, 8 y^{50} is equivalent to  (64 y Superscript 100 Baseline) Superscript one-half.

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What is ─7g + 5 = 2 – g – 7g solved to the variable???
Thepotemich [5.8K]

Answer:

g = -3

Step-by-step explanation:

-7g + 5 = 2 – g – 7g

Combine like terms

-7g + 5 = 2 -8g

5 = 2 + -g

3 = -g

-3 = g

4 0
3 years ago
A student working on a summer internship in the economic research department of a large corporation studied the relation between
OverLord2011 [107]

Answer:

Step-by-step explanation:

Hello!

Y: sales of a product in a marketing district (million dollars)

X: population in a marketing district (million persons)

The objective is to test if there is a linear association between the sales of a product and the population of a marketing district.

Parameter; Estimated Value; 95 Percent Confidence limits

Intercept          7.43119                -1.18518        16.0476

Slope             0.755048            0.452886       1.05721

a.

To test if there is or not an association between these two variables, you have to do a hypothesis test for the slope. If the slope is equal to zero, there is no linear association between the two variables, if the slope is different from zero, then there is a linear association between the variables.

So the student's hypotheses are:

H₀: β = 0

H₁: β ≠ 0

The data the student used to conclude is the 95%CI for the slope [0.452886;1.05721]

To be able to decide over an hypothesis test using a confidence interval there are several conditions to be met, one of them is that the confidence level and the significance level should be complementary, this means that if the interval was constructed using 1 - α= 0.95, then the hypothesis test should be conducted with a significance level of α= 0.05.

Considering that the value of the slope stated in the null hypothesis is not included in the given interval, i.e. zero is not included in the CI, then the decision is to reject the null hypothesis.

Then it can be concluded that there is a linear association between the sales of a product and the population in a marketing district.

b.

Although in the context of the variables of study it makes no sense that the estimate of the intercept takes negative numbers, keep in mind that mathematically if possible and correct. This means that obtaining a negative estimate of the intercept does not represent a calculation error or problem for the regression model. In general, when this occurs, a footnote is made indicating has no biological meaning or sense in context.

After all, what you have done with the estimate is a mathematical assertion of the social variables.

I hope it helps!

3 0
3 years ago
Evaluate (-12)(-2) ^2
vazorg [7]

Answer:

- 48

Step-by-step explanation:

by PEDMAS, we evaluate the exponent first before the multiplication

(-12)·(-2)²  

= (-12)·(4)

= - 48

7 0
3 years ago
Ron Haslam gets a Social Security benefit of $1,200 per month. His wife receives a benefit equal to 40 percent of Ron's benefit.
mr Goodwill [35]
The awnser would be $230
5 0
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The pair of square pyramids are similar. Use the given information to find the scale factor of the smaller square pyramid to the
Mrrafil [7]
\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array}\\\\
-----------------------------

\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\
\stackrel{\stackrel{pyramids}{scale~factor}}{\cfrac{small}{large}}\qquad \qquad \cfrac{s}{s}=\cfrac{\sqrt[3]{64}}{\sqrt[3]{343}}\implies \cfrac{s}{s}=\cfrac{4}{7}\implies 4:7
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