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lord [1]
3 years ago
10

Is 5 yards larger then 192 inches

Mathematics
1 answer:
disa [49]3 years ago
8 0
No, 5 yards is NOT larger than 192 inches.

We can easily convert 5 yards into inches, or convert 192 inches into yards to get our answer.

1 yard = 36 inches, so do \longrightarrow 5 × 36 to get 180 inches.

Now, we already can tell that 180 inches is NOT larger than 192 inches, so the answer is no. As I said before, you could also convert 192 inches into yards to get the answer as well. 
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Use calculus to find the volume of the following solid SThe base of S
Elanso [62]

Answer:

difficult Dino x shock so zero shock still is romp

8 0
2 years ago
The probability of a football team winning a game is three fifths. If they play 45 games in a season, how many games would you e
Charra [1.4K]

Answer:

27 games

Step-by-step explanation:

The probability of them winning is 3 out of 5 games.

First, multiply 45 by \frac{3}{5}

\frac{45}{1} *\frac{3}{5}

\frac{135}{5}

27 games.

<u />

You could also just multiply 45 by 3 then divide by 5. Mostly the same thing

I hope this helps!

8 0
3 years ago
Find the perimeter of the window. Round your answer to the nearest tenth.
liberstina [14]
1) The perimeter is the sum of the lengths of the straight edge (the diameter of the semicircle) and the length of the arc of the semicircle.

The circumference of a 4 ft circle is
  π*diameter = π*4 ft ≈ 12.566 ft
The semicircle will have a length that is half that, 6.283 ft. When this length is added to the diameter, the perimeter is found to be
  Perimeter = 4 ft + 6.283 ft ≈ 10.3 ft.


2) The area of a circle is given by the formula
  A = (π/4)d²
For a diameter of 15 inches, the area is
  A = (π/4)(15 in)² = 56.25π in²
  A ≈ 176.7146 in²

The area of the circle is about 176.71 in².
5 0
3 years ago
Last year, Mr. Jones made $30,000. His boss just informed him that he will be receiving at least an 11.2% raise for this year. H
Lady bird [3.3K]

Answer:

$33 336

Step-by-step explanation:

Increase = 30 000 × 0.112

Increase = $3336

New salary = 30 000 + 3336

New salary = $33 336

7 0
3 years ago
The USDA conducted tests for salmonella in produce grown in California. In an independent sample of 252 cultures obtained from w
Marat540 [252]

Answer:

 The decision rule is  

Fail to reject the null hypothesis

  The conclusion is  

There no sufficient evidence to show that the proportion of salmonella in the region’s water differs from the proportion of salmonella in the region’s wildlife

Step-by-step explanation:

From the question we are told that

   The first  sample size is n_1   =  252

    The number that tested positive is  k_1  =  18

     The second sample size is  n_2   =  476

     The number that  tested positive is  k_2 =  20

     The level of significance is  \alpha  = 0.01

Generally the first sample proportion is mathematically represented as

      \^ p _1 =  \frac{k_1 }{ n_1 }

=>    \^ p _1 =  \frac{18 }{ 252 }

=>    \^ p _1 = 0.071

Generally the second sample proportion is mathematically represented as

      \^ p _2 =  \frac{k_2 }{ n_2 }

=>    \^ p _2 =  \frac{20 }{ 476}

=>    \^ p _2 = 0.042

The  null hypothesis is            H_o  :  p_1 - p_2 = 0

The alternative hypothesis is  H_a :  p_1 - p_2 \ne 0

Generally the test statistics is mathematically represented

       z =  \frac{ \^ p_1 - \^ p_2  -  ( p_ 1 - p_2 )}{ \sqrt{\frac{\^ p_1 (1-\^ p_1)}{ n_1  } + \frac{\^ p_2 (1-\^ p_2)}{ n_2  }  } }

=>    z =  \frac{ 0.071 - 0.042  - 0 }{ \sqrt{\frac{0.071  (1-0.071)}{  252  } + \frac{0.042 (1-\^ 0.042)}{ 476  }  } }

=>    z =  1.56

From the z table  the area under the normal curve to the right corresponding to  1.56   is  

        P(Z >  1.56 ) =0.05938

Generally the p-value is mathematically represented as

         p-value =  2 * P(Z >  1.56 )

=>      p-value = 2 *  0.05938

=>      p-value = 0.1188

From the value obtained we see that   p-value  >  \alpha hence

  The decision rule is  

Fail to reject the null hypothesis

  The conclusion is  

There no sufficient evidence to show that the proportion of salmonella in the region’s water differs from the proportion of salmonella in the region’s wildlife

 

5 0
2 years ago
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