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Hitman42 [59]
3 years ago
8

If the point (p,-5) is on the graph of the equation 6x-3y=21, find the value of p

Mathematics
1 answer:
miv72 [106K]3 years ago
3 0

\bf (\stackrel{\stackrel{x}{\downarrow }}{p},\stackrel{\stackrel{y}{\downarrow }}{-5})~\hspace{10em}6x-3y=21\implies 6x-3\stackrel{\stackrel{y}{\downarrow }}{(-5)}=21 \\\\\\ 6x+15=21\implies 6x=6\implies x=\cfrac{6}{6}\implies \stackrel{\stackrel{p}{\uparrow }}{x}=1

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Please help!!
timofeeve [1]

Answer:

y = 2/3x

Step-by-step explanation:

So we know, when lines are perpendicular that they share the same slope. The slope in the equation of y = 2/3x + 7 is 2/3x. So, we have our slope. Now, we just need to find our b. We plug in the point that you gave us into the equation y = mx + b.

3 = 2/3(2) + b

we multiply the denominator 3 by 2, then divide that by the numerator 2.

3 = 3 + b

subtract 3 from itself and from the opposite side of the equal side 3.

0 = b

in the end, there is no b for this equation. Our answer is

y = 2/3x

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