The moon is about 240,000 miles from earth what is this distance written as a whole number multiplied by a power of ten

Plants capturing light energy to from simple sugars using water and carbon dioxide is called

kotykmax [81]

Answer:

During the process of photosynthesis, chlorophyll within the leaves of plants captures light energy from the Sun to produce simple sugars. ... During photosynthesis, plant cells take in water (H2O) and carbon dioxide (CO2) and release oxygen (O2).

Step-by-step explanation:

3 0

3 years ago

Convert 444 yards to meters. Use 1 yard = 0.9144 meters

Nitella [24]

Answer:

405.9936 meters

Step-by-step explanation:

We know that

1 yard = 0.9144 meters

We are converting 444 yds to meters

444 yds * .9144 meters/ 1 yds = 405.9936 meters

4 0

3 years ago

A photoconductor film is manufactured at a nominal thickness of 25 mils. The product engineer wishes to increase the mean speed

AURORKA [14]

Answer:

A 98% confidence interval estimate for the difference in mean speed of the films is [-0.042, 0.222].

Step-by-step explanation:

We are given that Eight samples of each film thickness are manufactured in a pilot production process, and the film speed (in microjoules per square inch) is measured.

For the 25-mil film, the sample data result is: Mean Standard deviation 1.15 0.11 and For the 20-mil film the data yield: Mean Standard deviation 1.06 0.09.

Firstly, the pivotal quantity for finding the confidence interval for the difference in population mean is given by;

P.Q. = $\frac{(\bar X_1 -\bar X_2)-(\mu_1- \mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t__n_1_+_n_2_-_2$

where, $\bar X_1$ = sample mean speed for the 25-mil film = 1.15

$\bar X_1$ = sample mean speed for the 20-mil film = 1.06

$s_1$ = sample standard deviation for the 25-mil film = 0.11

$s_2$ = sample standard deviation for the 20-mil film = 0.09

$n_1$ = sample of 25-mil film = 8

$n_2$ = sample of 20-mil film = 8

$\mu_1$ = population mean speed for the 25-mil film

$\mu_2$ = population mean speed for the 20-mil film

Also, $s_p =\sqrt{\frac{(n_1-1)s_1^{2}+ (n_2-1)s_2^{2}}{n_1+n_2-2} }$ = $\sqrt{\frac{(8-1)\times 0.11^{2}+ (8-1)\times 0.09^{2}}{8+8-2} }$ = 0.1005

Here for constructing a 98% confidence interval we have used a Two-sample t-test statistics because we don't know about population standard deviations.

So, 98% confidence interval for the difference in population means, ( $\mu_1-\mu_2$ ) is;

P(-2.624 < $t_1_4$ < 2.624) = 0.98 {As the critical value of t at 14 degrees of

freedom are -2.624 & 2.624 with P = 1%}

P(-2.624 < $\frac{(\bar X_1 -\bar X_2)-(\mu_1- \mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ < 2.624) = 0.98

P( $-2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ < $2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ < ) = 0.98

P( $(\bar X_1-\bar X_2)-2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ < ( $\mu_1-\mu_2$ ) < $(\bar X_1-\bar X_2)+2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ) = 0.98

98% confidence interval for ( $\mu_1-\mu_2$ ) = [ $(\bar X_1-\bar X_2)-2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ , $(\bar X_1-\bar X_2)+2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ]

= [ $(1.15-1.06)-2.624 \times {0.1005 \times \sqrt{\frac{1}{8}+\frac{1}{8} } }$ , $(1.15-1.06)+2.624 \times {0.1005 \times \sqrt{\frac{1}{8}+\frac{1}{8} } }$ ]

= [-0.042, 0.222]

Therefore, a 98% confidence interval estimate for the difference in mean speed of the films is [-0.042, 0.222].

Since the above interval contains 0; this means that decreasing the thickness of the film doesn't increase the speed of the film.

7 0

3 years ago

What is the area of this trapezoid? Enter your answer in the box.

mezya [45]

Answer:

352 ft²

Step-by-step explanation:

The formula for the area of a trapezoid is $A=(\frac{b_1+b_2}{2})h$ where $b_1$ and $b_2$ are the bases of the trapezoid and $h$ is the height, thus:

$A=(\frac{b_1+b_2}{2})h\\\\A=(\frac{13+31}{2})(16)\\\\A=(\frac{44}{2})(16)\\ \\A=(22)(16)\\\\A=352$

This means that the area of the trapezoid is 352 ft².

5 0

2 years ago

Write an equation that you can use to find the value of x.

MariettaO [177]

Line CA is a straight line, meaning it adds up to 180°

Line BE splits the line into two supplementary angles, because when the two angles are added together they will equal 180°

Using the rule of supplementary angles, we can then make the equation 3x + 8x + 15 = 180

Now, simplify the equation by combining like terms

11x + 15 = 180

To solve, isolate x

11x + 15 = 180
11x = 165
x = 15

7 0

2 years ago