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3 years ago

If you help me get this right i will give you brainly, and 5 stars! tysm

Mathematics

2 answers:

9966 [12]3 years ago

7 0

Answer:

1.a

2.b

Step-by-step explanation:

The first column is the domain, while the second column is the range. Therefore, 1 is a, and 2 is b. Hope this helps!

storchak [24]3 years ago

6 0

Answer
1. A
2.B

The domain is the left side and the Range is the right

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2 + y + y + y + y + y + 3 ?

Temka [501]

Answer:

5 + 5y

Step-by-step explanation:

2 + y + y + y + y + y + 3

Combine like terms

2+3 + y + y + y + y + y

5 + 5y

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3 years ago

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A car can go 35 1/2 miles in 1 1/2 miles gallons. How many gallons does a car need to go 639 miles?

Mnenie [13.5K]

Answer: 27 gallons

Step-by-step explanation:

Since the car can go 35½ miles in 1½ miles gallons, we need to first calculate the number of miles that the car can go in 1 gallon. This will be:

= 35½ / 1½

= 71/2 / 3/2

= 71/2 × 2/3

= 23⅔ miles per gallon.

Therefore, the amount of gallons that the car need to go 639 miles will be:

= 639 / 23⅔

= 639 ÷ 71/3

= 639 × 3/71

= 27

The car will need 27 gallons.

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3 years ago

Which expression shows the sum 9 + 21 rewritten as a product of the GCF and a sum?

Andrej [43]

B.
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21 = 3 x 7
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4 years ago

QUESTION 5

Anni [7]

Answer: 2/13

Step-by-step explanation:

4 aces, 4 nines in a deck of 52 cards

so 8/52 chance of getting one of them reduce to 2/13

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3 years ago

On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

Elena L [17]

Answer:

The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, a = $\sqrt{(3-0)^{2}+(4-0)^{2}}$

Or, a = $\sqrt{9+16}$

Or, a = $\sqrt{25}$

∴ a = 5 unit

Similarly

The measure of length BC = b = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, b = $\sqrt{(3-3)^{2}+(2-4)^{2}}$

Or, a = $\sqrt{0+4}$

Or, b = $\sqrt{4}$

∴ b = 2 unit

And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, c = $\sqrt{(3-0)^{2}+(2-0)^{2}}$

Or, c = $\sqrt{9+4}$

Or, c = $\sqrt{13}$

∴ c = $\sqrt{13}$ unit

Now, area of Triangle written as , from Heron's formula

A = $\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

and s = $\frac{a+b+c}{2}$

I.e s = $\frac{5+2+\sqrt{13}}{2}$

Or. s = $\frac{7+\sqrt{13}}{2}$

So, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}$

Or, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}$

Or, A = $\frac{3}{2}$ × $\sqrt{1+\sqrt{13} }$

∴ Area of triangle = 1.5 $\sqrt{4.6}$

Hence The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$ Answer

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3 years ago

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