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aliina [53]
2 years ago
13

If you help me get this right i will give you brainly, and 5 stars! tysm

Mathematics
2 answers:
9966 [12]2 years ago
7 0

Answer:

1.a

2.b

Step-by-step explanation:

The first column is the domain, while the second column is the range. Therefore, 1 is a, and 2 is b. Hope this helps!

storchak [24]2 years ago
6 0
Answer
1. A
2.B

The domain is the left side and the Range is the right
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Allison has an account balance of -$50.15. Does Allison owe the bank more or less than $50?
Whitepunk [10]

Answer: Allison owes the bank more then $50

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2 years ago
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Which is the best estimate of the correlation coefficient for the scatter plot?
olga55 [171]

Answer:

The best estimate of the correlation coefficient is 0.9 from the given data.

Step-by-step explanation:

From the scatter plot, the line of best fit will have a positive slope.

So, the correlation coefficient , \rho is greater than 0.

so, \rho ≠ - 0.9

Also, there is a deviation from absolute linearity.

So, \rho ≠ 1

Again from the scatter plot it is closer to linearity than further.

Hence, \rho ≠ 0.3 .

So \rho = 0.9

6 0
3 years ago
Need help again, I really hate math please help​
hoa [83]
C I think good luck
3 0
2 years ago
Select the relations that are functions.
Arlecino [84]

Answer:

Depending on how the input of each function defined,

  • The first choice \left\lbrace(a, 1),\, (6, 1), \, (C, 1)\right\rbrace,
  • The third choice \left\lbrace(1, a),\, (2, a), \, (3, a)\right\rbrace
  • The fourth choice \left\lbrace(a, a),\, (b, b), \, (c, c)\right\rbrace

might be functions.

Step-by-step explanation:

A function between two sets (domain and range) should

  • be defined for all elements in the domain, and
  • map each element from the domain to exactly one element in the range.

The second choice can't be a function since the element a from the domain is mapped to more than one element in the range.

Keep in mind that a function should be defined for all elements in its domain. For the first relation to be a function, its domain needs to be \lbrace a,\, 6, \, C\rbrace. Similarly, the domain for the third and fourth relations should be \lbrace 1,\, 2, \, 3\rbrace and \lbrace a,\, b, \, c\rbrace

8 0
3 years ago
In parallelogram QRST QS RT Is QRST a rectangle ?
fomenos

Answer:

The correct option is A.

Step-by-step explanation:

It is given that the QRST is a parallelogram and the diagonals QS and RT are congruent.

According to the property of parallelogram if the length of diagonals are same, then the parallelogram is rectangle. We can also prove it.

Let QRST be an parallelogram and QS=RT.

In triangles QRT and RQS.

RT=QS         (Diagonals)

QR=QR         (Common side)

QT=RS         (Opposite sides of the parallelogram are same)

So by SSS rule of congruence, triangle QRT and triangle RQS are congruent.

By CPCT,

\angle R=\angle Q

Since the sum of two consecutive angles of a parallelogram is 180 degree.

\angle R+\angle Q=180

2\angle R=180

\angle R=90

Therefore the measure of angle R and angle Q are 90 degree.

Similarly in triangle QST and RTS,

RT=QS         (Diagonals)

ST=ST         (Common side)

QT=RS         (Opposite sides of the parallelogram are same)

So by SSS rule of congruence, triangle QST and RTS are congruent.

By CPCT,

\angle S=\angle T

Since the sum of two consecutive angles of a parallelogram is 180 degree.

Therefore the measure of angle S and angle T are 90 degree.

Since the measure of all interior angles of QRST are 90 degree, therefore the parallelogram QRST  is a rectangle.

6 0
3 years ago
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