Answer:
The answer is "MS and QS".
Step-by-step explanation:
Given ΔMNQ is isosceles with base MQ, and NR and MQ bisect each other at S. we have to prove that ΔMNS ≅ ΔQNS.
As NR and MQ bisect each other at S
⇒ segments MS and SQ are therefore congruent by the definition of bisector i.e MS=SQ
In ΔMNS and ΔQNS
MN=QN (∵ MNQ is isosceles triangle)
∠NMS=∠NQS (∵ MNQ is isosceles triangle)
MS=SQ (Given)
By SAS rule, ΔMNS ≅ ΔQNS.
Hence, segments MS and SQ are therefore congruent by the definition of bisector.
The correct option is MS and QS
ok so here we go:
1) 
or 
2 )
so the answer is (0, -4) or -4
3) y=
4) y=[tex]\frac{3}{2}x+1[tex] so the answer is (0, 1) or 1
Answer:
2 x 7
Step-by-step explanation:
a * b = 14
2a + 2b = 18
(a * b)/b = 14/b Dividing both sides by b
a = 14/b
Substitute a in the perimeter equation
2(14/b) + 2b = 18
28/b + 2b = 18
2b - 18 + 28/b = 0
Multiply both sides by b
2b^2 - 18b + 28 = 0
Divide both sides by two
b^2 - 9b + 14 = 0
The Factors of 14 include -2 and -7 which add up to -9
(b - 2) * (b - 7) = 0
This has two answers because b can be either the side that is 2 long or 7 long, so there's no need to go back and solve for a.
2 x 7
You know that BC is congruent to x so you need to solve for x using the ratio:
So then we need to find BC.
We know:
Therefore BC =8
Then:
