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katovenus [111]
3 years ago
13

Resolver la inecuacion 3x -14 <7x -2

Mathematics
1 answer:
aniked [119]3 years ago
8 0
The answer to this question is: x>-3
3x-14<7x-2
3x<7x+12
-4x<12
4x>-12
x>-3

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The LCM of 6 and 4, is 12.
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What's The slope intercept form of: x - y = 7
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Y=x-7 this is because you subtracted the x to both sides. Since y is a negative, you divide by -1 causing the -x to turn positive and the positive seven to be negative seven. 

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the GCF of two numbers is 850 number is divisible by the other what is the smallest these two numbers can be
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3 years ago
According to the Rational Root Theorem, the following are potential roots of f(x) = 2x2 + 2x – 24.
Andrei [34K]

Answer:

The answer is 3 and (-4).

Step-by-step explanation:

We are given an equation 2x² + 2x – 24.

Let us assume that the equation is equal to zero.

2x² + 2x – 24 = 0

Now, divide whole equation by 2 we get,

x² + x – 12 = 0

x² + 4x – 3x – 12 = 0

x(x + 4) – 3(x + 4) = 0

(x – 3) (x + 4) = 0

x = 3, -4

Thus, The actual roots of f(x) are 3 and (-4).

7 0
2 years ago
Write an equation for a quadratic function that has x intercepts (-3, 0) and (5, 0)
Blizzard [7]

Answer:

One possible equation is f(x) = (x + 3)\, (x - 5), which is equivalent to f(x) = x^{2} - 2\, x - 15.

Step-by-step explanation:

The factor theorem states that if x = x_{0}  (where x_{0} is a constant) is a root of a function, (x - x_{0}) would be a factor of that function.

The question states that (-3,\, 0) and (5,\, 0) are x-intercepts of this function. In other words, x = -3 and x = 5 would both set the value of this quadratic function to 0. Thus, x = -3\! and x = 5\! would be two roots of this function.

By the factor theorem, (x - (-3)) and (x - 5) would be two factors of this function.

Because the function in this question is quadratic, (x - (-3)) and (x - 5) would be the only two factors of this function. In other words, for some constant a (a \ne 0):

f(x) = a\, (x - (-3))\, (x - 5).

Simplify to obtain:

f(x) = a\, (x + 3)\, (x - 5).

Expand this expression to obtain:

f(x) = a\, (x^{2} - 2\, x - 15).

(Quadratic functions are polynomials of degree two. If this function has any factor other than (x - (-3)) and (x - 5), expanding the expression would give a polynomial of degree at least three- not quadratic.)

Every non-zero value of a corresponds to a distinct quadratic function with x-intercepts (-3,\, 0) and (5,\, 0). For example, with a = 1:

f(x) = (x + 3)\, (x - 5), or equivalently,

f(x) = x^{2} - 2\, x - 15.

6 0
2 years ago
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