1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Montano1993 [528]
1 year ago
12

an urn contains 5 blue balls and 7 orange balls. in how many ways can we select 3 blue balls and 5 orange balls from the urn?

Mathematics
1 answer:
Temka [501]1 year ago
3 0

The no. of ways to select the 3 blue balls and 5 orange balls from the urn is 0.424

No. of Blue balls in the urn = 5

No. of Orange balls in the urn = 7

Total no. of balls in the urn = No. of blue balls + No. of orange balls

                                             = 5 + 7

                                            = 12 balls

No. of blue balls to be selected = 3

No. of orange balls to be selected = 5

No. of balls to be selected = 8

The total. no of ways 8 balls can be selected = 12C₈

The No. of ways 3 blue balls can be selected = 5C₃

The No. of ways 5 orange balls can be selected = 7C₅

Therefore, No. of ways to select 3 blue balls and 5 orange balls from the urn

                       =  5C₃ x  7C₅ / 12C₈

[ Probability = No. of ways to select blue balls x No. of ways to select orange balls / Total no. of ways to select balls]

               

                P = 10 x 21 / 495

                   = 210 / 495

                P = 0.424

Therefore,  the no. of ways to select blue and orange balls is 0.424

Learn more about the probability in

brainly.com/question/11234923

#SPJ4

You might be interested in
How many bits are required to represent the decimal numbers in the range from 0 to 999 in straight binary code?
ad-work [718]
Note that powers of 2 can be written in binary as

2^0=1_2
2^1=10_2
2^2=100_2

and so on. Observe that n+1 digits are required to represent the n-th power of 2 in binary.

Also observe that

\log_2(2^n)=n\log_22=n

so we need only add 1 to the logarithm to find the number of binary digits needed to represent powers of 2. For any other number (non-power-of-2), we would need to round down the logarithm to the nearest integer, since for example,

2_{10}=10_2\iff\log_2(2^1)=\log_22=1
3_{10}=11_2\iff\log_23=1+(\text{some number between 0 and 1})
4_{10}=100_2\iff\log_24=2

That is, both 2 and 3 require only two binary digits, so we don't care about the decimal part of \log_23. We only need the integer part, \lfloor\log_23\rfloor, then we add 1.

Now, 2^9=512, and 999 falls between these consecutive powers of 2. That means

\log_2999=9+\text{(some number between 0 and 1})

which means 999 requires \lfloor\log_2999\rfloor+1=9+1=10 binary digits.

Your question seems to ask how many binary digits in total you need to represent all of the numbers 0-999. That would depend on how you encode numbers that requires less than 10 digits, like 1. Do you simply write 1_2? Or do you pad this number with 0s to get 10 digits, i.e. 0000000001_2? In the latter case, the answer is obvious; 1000\times10=10^4 total binary digits are needed.

In the latter case, there's a bit more work involved, but really it's just a matter of finding how many number lie between successive powers of 2. For instance, 0 and 1 both require one digit, 2 and 3 require two, while 4-7 require three, while 8-15 require four, and so on.
8 0
3 years ago
What’s the value of y?
xenn [34]

Answer:

c. 19

Step-by-step explanation:

This model is describing a function. You put in a number for x, in this case, the input of 7 on the side. You solve the equation with that x-value to get a y-value/output.

x=7

y=3x-2

y=3(7)-2

y=21-2

y=19

7 0
3 years ago
A number cube has sides that are labeled 1 to 6. Jamal rolls the number cube. What is the probability that he will roll a 22?
Tems11 [23]

-- The probability of rolling a 22 is zero.  That result is impossible, because the sides are labeled with single digits 1 through 6 .  Since 22 is not printed anywhere on the cube, it can never come up.

-- The probability of rolling a<em> 2</em> , however, is <em> 1/6</em> . <em>(B)</em>

<em></em>

The -probability of rolling something you want is always

<em>(the number of different possible results that you like) </em>

divided by

<em>(the total number of different possible results)</em>

4 0
3 years ago
Please solve eedfefsre3dfve
Lubov Fominskaja [6]
It will be 6 cause it is going by 1+ 1,2,3,4,5,6 (if it was 1,3,6,9, it will be 12 cause it is going by 3+) so answer is 6
5 0
2 years ago
Read 2 more answers
PLEASE HELP ASAP
butalik [34]

Answer: Dilation followed by a rotation & they are similar.

Step-by-step explanation:

3 0
2 years ago
Other questions:
  • Choose the correct equation for the line shown on the graph?
    15·2 answers
  • Month 0 1 2 3 length 5 6 7 8 input output table graph
    11·1 answer
  • ou purchase a computer for $755.00 plus 5% sales tax. You decide to finance it through the store's 0% interest program for six m
    15·1 answer
  • Estimate the product of 54x68
    14·2 answers
  • Which of the following options have the same value as 62% of 45?
    6·1 answer
  • Find the equation of the line passing through the point (–1, –2) and perpendicular to the line y = –1∕2x + 5. Choices are in the
    10·1 answer
  • Operations
    12·1 answer
  • Solving Quadratics<br><br><br><br> Solve for all values of x by factoring. x² + 4x + 5 = -6x + 5​
    11·1 answer
  • What is the solution to the system of equations graphed below? (0, 4) (1, 3) (3, 1) (4, 0)
    5·1 answer
  • PLZ HELP IM IN 8TH GRADE
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!