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Ad libitum [116K]
3 years ago
13

How many dimes in 290

Mathematics
2 answers:
uranmaximum [27]3 years ago
6 0
$1 = 10 dimes
$290 = 2,900 dimes

Hope that helps :)
yarga [219]3 years ago
5 0
In $1, there are 10 dimes
In $290, there will be 2,900 dimes.
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Mala has a collection of bangles. She has 20 gold bangles and 10 silver bangles. What is the percentage of bangles of each type?
Rainbow [258]

Answer:

Percentage of gold bangles is 66.6 and of silver bangles it is 33.3

Step-by-step explanation:

Given:

Number of gold bangles Mala has = 20

Number of silver bangles she has  = 10

Total number of bangles = 20+10 = 30

We have to find the percentage of each type of bangles.

So,

Percentage of bangles  = \frac{No.\ of \ bangles\ each\ type}{Total\ no.\ of \ bangles} \times 100

  • Percentage of gold bangles.

        ⇒ \frac{20}{30} \times 100

        ⇒ \frac{20\times 100}{30}

        ⇒ \frac{2000}{30}

        ⇒ \frac{200}{3}

        ⇒ 66.6\%

  • Percentage of silver bangles.

       ⇒ \frac{10}{30}\times 100

       ⇒ 33.3\%

Percentage of gold bangles, Mala has = 66.6 and of silver bangles it is = 33.3

7 0
3 years ago
Wrote an equation to find x
Igoryamba
3x+1+52 = 180°

Remember, angles in a straight line must ALWAYS add up to 180°.
7 0
3 years ago
Which algebraic expression means “four less than three times a number”?
Monica [59]

It’s 3n-4

I might be right or wrong

5 0
3 years ago
Research suggests that about 60% of CSU graduates started at a community college. In random samples of 100 CSU graduates, the pe
Nesterboy [21]

Answer:

The probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% is 0.6923.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

 \sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

The information provided is:

<em>p</em> = 0.60

<em>n</em> = 100

As <em>n</em> = 100 > 30, the central limit theorem can be applied to approximate the sampling distribution of sample proportions.

The distribution of sample proportion is \hat p\sim N(0.60, 0.049^{2}).

Compute the probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% as follows:

P(|\hat p-\mu_{\hat p}|=0.05)=P(-0.05

                             =P(\frac{-0.05}{0.049}

Thus, the probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% is 0.6923.

8 0
3 years ago
What is the fraction 1/4 , 2/5 , 1/5 , 2/4
Artyom0805 [142]

Answer:

1/4

Step-by-step explanation:

count the gaps in between

7 0
3 years ago
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