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Gekata [30.6K]
3 years ago
9

By the age of 21, the best violinist and pianist will have practiced at least 10,000 hours. If you practice and instrument 45 mi

nutes (or 0.75 hours) a day for 365.25 days, the length of a year, how many hours will you have practiced?
Mathematics
1 answer:
Alika [10]3 years ago
8 0

Answer:

273.94 hours.

Step-by-step explanation:

1 day = 0.75 hours of practicing in a day.

365.25 = x

1/365.25 = 0.75/x        Cross multiply

x = 0.75 * 365.25        Combine

x =  273.94 hours

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Need help on the answer
lions [1.4K]

Answer:

The second choice is the answer.

Step-by-step explanation:

In math, there are two types of numbers: real numbers and imaginary numbers. Imaginary numbers build upon the premise that the equation

x^2 +1 = 0 has no real solution. It is said that one of the imaginary solutions to this equation is <em>i</em>, or √-1. Real numbers are numbers that can represent the "distance" of a line. Real numbers have subsets known as natural numbers, whole numbers, integers, natural numbers. It also has a region of irrational numbers.

Natural numbers are numbers you use to count w/ your fingers (1, 2, 3 ...)

Whole numbers are natural numbers and 0 (0, 1, 2, 3 ...)

Integers are whole numbers and their opposites ( -1, 0, 1, ...)

Rational numbers integers and numbers that can be put into a fraction of two integers. for example, 1/2 is a fraction of the integers 1 and 2 ( -1, -1/2, 0, 1/2, 1 ...)

Irrational numbers are numbers that cannot be written as a simple fraction or cannot be written as terminating or repeating decimals (√2, π, <em>e, ...</em>).

The answer is not the first choice because it has whole numbers.

The answer is not the third choice because it has integers.

The answer is not the fourth choice because it has irrational numbers.

The answer is not the fifth choice because it has imaginary numbers.

The second choice is the one that has rational numbers and is the answer.

4 0
3 years ago
an octagon has sides that all have a length of y. Write a simplified algebraic expression for the perimeter of the octagon in te
padilas [110]

Answer = 8y

Step-by-step explanation:

if an octagon has 8 sides and each side is = to y then the total side length in the primiter is = to 8sides times y or 8y

5 0
2 years ago
1) check if they given ordered pairs are solutions to the equation or not.
ziro4ka [17]
Answer: a) Yes
b) No


Explanation: Substitute the values of X and Y from the given points into the equation. I’ll use a) as an example:
Given point: (1,-3)
Equation: 4x-2y=10
Value of X: 1
Value of Y: -3
Substitute X and Y: 4(1)-2(-3)=10
4-(-6)=10
4+6=10 ✔︎

Therefore, the given ordered pair is a proper solution to the equation 4x-2y=10.

*You can use the same method for question b).*
3 0
3 years ago
Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-ma
pickupchik [31]

Answer:

Answer explained below

Step-by-step explanation:

Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-mails containing the same virus, after which the virus disables itself on that machine. (1) Write a recursive definition (i.e. recurrence relation) to show how many spam emails will be sent out after n seconds. (2) Solve the recurrence relation. (3) How many e-mails are sent at the end of 20 seconds

1.START T=0.....

1000 EMAILS SENT AND RECEIVED BY 1000 M/CS.

T=1.....

EACH OF THE M/C SENDS 10 NEW MAILS ....

.................................

LET M[N] BE THE NUMBER OF MAILS SENT OUT AFTER N SECONDS.

SO , EACH OF THESE M/CS WILL SEND 10 MAILS IN NEXT 1 SECOND.

HENCE NUMBER OF MAILS SENT IN N+1 SECONDS=M[N+1]=

M[N+1]=10*M[N].......................1

THIS IS THE RECURRENCE RELATION.....

2.SOLUTION .....

M[N+1]=10M[N]=10*10M[N-1]=10*10*10M[N-2]=........

M(N+1)=[10^1][M(N)]=[10^2][M(N-1)]=[10^3][M(N-2)]=..........=[10^N][M(1)]=[10^(N+1)][M(0)]

M[N+1]=[10^(N+1)][1000]=[10^(N+1)][10^3]=[10^(N+4)]......................................2

THIS IS THE NUMBER OF MAILS SENT AFTER N+1 SECONDS .....OR ....

M[N]=[10^(N+3)].............................................3

..................IS THE SOLUTION FOR NUMBER OF MAILS SENT AFTER N SECONDS.....

3.AFTER N=20 SECONDS , THE ANSWER IS ....

M[20]=10^(20+3)=10^23

8 0
3 years ago
Read 2 more answers
Two students walk in the same direction along a straight path, at a constant speed - one at .90 m/s and the other at 1.90 m/s.a.
anyanavicka [17]

Answer:

a)The second student arrive 7 minutes and 36 seconds sooner

b)They have to walk 598,51 m

Step-by-step explanation:

Speed= Distance/Time

We are looking for time now

Time = Distance/Speed

First student

Time = 780 m/0.90 m/s=866,66 seconds

Second student

Time = 780 m/1.90 m/s=410,52 seconds

Difference=866,66-410,52= 456,14 seconds

In minutes

Difference= 456,14 seconds /60=7 minutes 36 seconds

Distance=Speed x Time

Speed¹ x Time¹ =Speed² x Time²

Time¹= Time² + 5.50 min

5.50 min =350 seconds

Time²  =Speed¹ x Time¹ /Speed²

Time²  =Speed¹ x (Time² + 350 seconds  ) /Speed²

Time²  =0.9 x (Time² + 350 seconds  ) /1.9

Time²  =0,4737 x (Time² + 350 seconds  )

Time²  =0,4737 Time² + 165,79 seconds

Time²  - 0,4737 Time² = 165,79 seconds

0,5263 Time² = 165,79 seconds

Time² = 165,79 seconds/0,5263 =315,01 seconds

Distance=1,9 x 315,01 seconds = 598,51 m

5 0
3 years ago
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