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valina [46]
3 years ago
14

Change 2 21/9 to an improper fraction

Mathematics
2 answers:
ivanzaharov [21]3 years ago
8 0

Answer: 13/3

Step-by-step explanation: TO turn a mixed number into an improper fraction, the best way is to multiply the denominator of the fraction by the whole number, then add the product to the numerator, then use that as the numerator of your new improper fraction, keeping the denominator the same.

>2 21/9

> 9*2 +21 =39

> 39/9

>13/3

levacccp [35]3 years ago
4 0
U have to multiply 2 times 9 and you’ll get 18, but then you have to add 18 and 21 and you’ll get 39, but you keep 9 as the denominator. So your answer would be 39/9.
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In order to solve this problem you need to divide both coefficients by 6 and factor the rest out.
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Evaluate the definite integral. 1/4 csc(2πt) cot(2πt) dt 1/12
Afina-wow [57]
Hey there, hope I can help!

\frac{1}{4}\csc \left(2\pi t\right)\cot \left(2\pi t\right)dt\frac{1}{12}

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\mathrm{Apply\:rule}\:1\cdot \:a=a \ \textgreater \  \frac{dt}{4\cdot \:12}\csc \left(2\pi t\right)\cot \left(2\pi t\right)

\mathrm{Multiply\:the\:numbers:}\:4\cdot \:12=48 \ \textgreater \  \frac{dt}{48}\csc \left(2\pi t\right)\cot \left(2\pi t\right)

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5 0
3 years ago
The sides of a triangle are x , x +1 , 2 x -1 and its area is x root of 10 .Find the value of x.
VARVARA [1.3K]


Ok, I'm going to start off saying there is probably an easier way of doing this that's right in front of my face, but I can't see it so I'm going to use Heron's formula, which is A=√[s(s-a)(s-b)(s-c)] where A is the area, s is the semiperimeter (half of the perimeter), and a, b, and c are the side lengths.

Substitute the known values into the formula:

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<span>x√10=√{[4x/2][(4x/2)-x][(4x/2)-(x+1)][(4x/2)-(2x-1)]}</span>

<span>x√10=√[2x(2x-x)(2x-x-1)(2x-2x+1)]</span>

<span>x√10=√[2x(x)(x-1)(1)]</span>

<span>x√10=√[2x²(x-1)]</span>

<span>x√10=√(2x³-2x²)</span>

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<span>2x²=0 or x-6=0</span>

<span>x=0 or x=6</span>

<span>Therefore, x=6 (you can't have a length of 0).</span>

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