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Anuta_ua [19.1K]
3 years ago
7

A publisher requires 2⁄3 of a page of advertisements for every 5 pages in a magazine. If a magazine has 98 pages, to the nearest

whole page, how many pages of the magazine are advertisements?
Mathematics
1 answer:
Ivanshal [37]3 years ago
3 0

To solve this problem you must apply the proccedure shown below:

  1. You have \frac{2}{3} of a page of advertisements for every 5 pages in the magazine and the it has 98 pages. Therefore, you must multiply the total pages by 2/3 and divide the result by 5 pages.
  2. Then:

x: number of pages of the magazine are advertisements

x=\frac{(98)(\frac{2}{3}) }{5} \\ x=13

Therefore, the answer is: 13 pages.

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Stels [109]
Y/22 would be the answer to your question.
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3 years ago
HELP
andreev551 [17]

Answer:

A. y = 80x

B. g(x) = 80x

C. To graph the equation, plot a point at (0,0) and a point at (1,80). Connect the points. Continue adding points by moving up $80 and over 1 day.

Step-by-step explanation:

Part A:  

To write an equation, use y= mx where m is the slope, x is the number of days, and y is the rent cost.

x and y remain the same in the equation.

To find m, use the slope formula with (5,465) and (7, 625).

m=\frac{y_2-y_1}{x_2-x_1}= \frac{625-465}{7-5} =\frac{160}{2} =80

It costs $80 a day.

The equation is y = 80x.

Part B:  

Function notation replaces Y as g(x). So the equation is g(x) = 80x.

Part C:

To graph the equation, plot a point at (0,0) and a point at (1,80). Connect the points. Continue adding points by moving up $80 and over 1 day.


6 0
3 years ago
Solve for a.<br> 7a + 18 = 102<br> a =
Virty [35]

Answer:

12

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A. Plot the data for the functions f(x) and g(x) on a grid and connect the points.
labwork [276]

Answer:

  a) see the plots below

  b) f(x) is exponential; g(x) is linear (see below for explanation)

  c) the function values are never equal

Step-by-step explanation:

a) a graph of the two function values is attached

__

b) Adjacent values of f(x) have a common ratio of 3, so f(x) is exponential (with a base of 3). Adjacent values of g(x) have a common difference of 2, so g(x) is linear (with a slope of 2).

__

c) At x ≥ 1, the slope of f(x) is greater than the slope of g(x), and the value of f(x) is greater than the value of g(x), so the curves can never cross for x > 1. Similarly, for x ≤ 0, the slope of f(x) is less than the slope of g(x). Once again, f(0) is greater than g(0), so the curves can never cross.

In the region between x=0 and x=1, f(x) remains greater than g(x). The smallest difference is about 0.73, near x = 0.545, where the slopes of the two functions are equal.

4 0
3 years ago
Find the slope of the line that contains the following points. R(-3, 5), S(3, -2) 7/6 7/6 undefined
Musya8 [376]

Answer:

-\frac{7}{6}

Step-by-step explanation:

We can use the slope formula for the segment that joins any two points (x_1, y_1) and (x_2, y_2):

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which in our case gives:

slope=\frac{y_2-y_1}{x_2-x_1}  = \frac{-2-5}{3-(-3)}=\frac{-7}{6} =-\frac{7}{6}

5 0
2 years ago
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