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3 years ago

11

–5 + 2n –11 or –6 – 10n > 44

1 answer:

ser-zykov [4K]3 years ago

4 0

Is part of the problem missing? There should be another set of numbers after -5+2n-11 so “n” can be isolated

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PLEASE HELP ME PRE CAL/TRIG

miss Akunina [59]

Answer:

A) 60 Degrees

B) 550 Feet

C) 2.5 minutes

Step-by-step explanation:

a) So the wheel has completed one revolution in 10 minutes so lets first divide 100 secs with 10 minutes to calculate the the fraction of revolution

1 min = 60 secs

10 min = 600 secs

100/600 = 1/6

One complete revolution is 360 degrees and 1/6 of 360 degrees will be 60 degrees .

360/6 = 60°

b) It takes 10 minutes to complete one revolution so if the person is on it for 7 minutes it would be 7/10 of a revolution . The ferris wheel has a diameter of 250 feet so the radius will be 125 feet because it is the half of the diameter and the circumference will be 250 π . To calculate the distance lets multiple the fraction of the revolution which is 7/10 into the circumference $\frac{7}{10} * (250 pi)$ = 550 Feet.

C)It took 10 minutes to travel 250 π now we will use this relation to calculate 200 feet . lets suppose t is for time .

$\frac{250pi}{10} =\frac{200}{t}$ .

After solving this equation as there is only one unknown which is "<em>t</em> "the answer will be 2.5 minutes.

3 0

3 years ago

What is the net force on a 1,000 kg object accelerating at 3 m/s2 ?

anzhelika [568]

3 $3 \leq m+1.4$

6 0

3 years ago

What do I do I’m lost I need help?

ale4655 [162]

Answer:

27

Step-by-step explanation:

the sequence is 4 added to each number. 4 added to 23 is 27

8 0

3 years ago

Read 2 more answers

Evaluate using <br> Definite integrals

swat32

Since $[0,4]=[0,1]\cup(1,4]$ , we can rewrite the integral as

$\displaystyle \int_0^1f(t)\;dt + \int_1^4 f(t)\; dt$

Now there is no ambiguity about the definition of f(t), because in each integral we are integrating a single part of its piecewise definition:

$\displaystyle \int_0^1f(t)\;dt = \int_0^11-3t^2\;dt,\quad \int_1^4 f(t)\; dt = \int_1^4 2t\; dt$

Both integrals are quite immediate: you only need to use the power rule

$\displaystyle \int x^n\;dx=\dfrac{x^{n+1}}{n+1}$

to get

$\displaystyle \int_0^11-3t^2\;dt = \left[t-t^3\right]_0^1,\quad \int_1^4 2t\; dt = \left[t^2\right]_1^4$

Now we only need to evaluate the antiderivatives:

$\left[t-t^3\right]_0^1 = 1-1^3=0,\quad \left[t^2\right]_1^4 = 4^2-1^2=15$

So, the final answer is 15.

4 0

4 years ago

on Tuesday pierce ran 3/4 mile and walked 3/4 on Wednesday he ran 2/4 mile and walk 1 1/4 miles hiw much farther did pierce run

Korvikt [17]

Answer:

On Tuesday

3/4 + 3/4 = 3/2 = 1 1/2 = 1.5

On Wednesday

2/4 + 1 1/4 = 7/4 = 1 3/4 = 1.75

Then we subtract

1.75 - 1.5 = 0.25

6 0

4 years ago

Read 2 more answers