<span>Northwest is 45 degrees north of west. If a car travels a distance x miles northwest, its northerly component gains x/sqrt(2) miles and its easterly component LOSES xsqrt(2)/ miles.
Resultant height is h = 4500 + 100x/sqrt(2) - 75x/sqrt(2) = [25/sqrt(2)]x + 4500
dh/dt = [25/sqrt(2)]dx/dt = [25/sqrt(2)]v </span>
Answer:
b) 2
Step-by-step explanation:
both angles have the same values, they are technically opposites.
Set your formula up as
130 = 66x - 2
130 + 2 = 66x
132/66 = x
2 = x
ANSWER IS D.
Process:
See in the attached fig,
BD=length of pole=?
AB=length of vertical(imagine)
BC=length of shadow=20 ft
In traingle ABC,
tan(36)=AB/BC
AB=tan(36)*20
AB=14.5308 ft
Now we find <BDC to use sine law.
For that,
<BDC+<DCB+<CBD=180
<BDC+36+(90+12)=180
<BDC=180-112-36
<BDC=42
Now we use sine law in traingle ABC,
BC/sin (<BDC) =BD/sin (<DCB)
20/sin(42)=BD/sin(36)
BD=(20*sin36)/sin42
BD=17.56=17.6(approx) >>>>>>>>ANSWER D