Ask question

Ask question

All categories

erma4kov [3.2K]

3 years ago

14

For Oscar's birthday, his grandparents gave him a 100 dollar gift card to a local movie theater. The theater charges 12 dollars

for each movie write an explicit and recursive rule for the sequence

1 answer:

olga_2 [115]3 years ago

4 0

Answer:

Move 100 to the left of a

100 a

List of all of the solutions

ax100=100a

12= 100a

You might be interested in

What is the value of x to the nearest tenth tan 64 degrees = x/7

Setler [38]

Tan64°=x/4⇒x=14.35≈14.4

7 0

3 years ago

Kitten leave the call daddys about to say something racist ^_^

SOVA2 [1]

Answer:

what is this??????????

5 0

3 years ago

Read 2 more answers

Solve the expression using pemdas (4+5)÷3×4

Dennis_Churaev [7]

1) you add the variables in the bracket

(4+5)÷3×4

9÷3×4

2) you multiply 3 by 4

9÷3×4

9÷12

3) now you divide 9 by 12

9÷12

=0.75

7 0

3 years ago

Read 2 more answers

SCALCET8 3.8.001.MI. A population of protozoa develops with a constant relative growth rate of 0.6137 per member per day. On day

Orlov [11]

Answer:

A population of protozoa develops with a constant relative growth rate of 0.6137 per member per day. On day zero the population · Q: For this discussion, you will work in groups to find the area and answer questions.

Step-by-step explanation:

3 0

3 years ago

In Exercises 10 and 11, points B and D are points of tangency. Find the value(s) of x.<br>

Lemur [1.5K]

In both cases,

$AB^2=AD^2$

(as a consequence of the interesecting secant-tangent theorem)

So we have

10.

$(4x+7)^2=(6x-3)^2$

$16x^2+56x+49=36x^2-36x+9$

$20x^2-92x-40=0$

$5x^2-23x-10=0$

$(5x+2)(x-5)=0\implies\boxed{x=5}$

(omit the negative solution because that would make at least one of AB or AD have negative length)

11.

$(4x^2-18x-10)^2=(x^2+x+4)^2$

$16x^4-144x^3+244x^2+360x+100=x^4+2x^3+9x^2+8x+16$

$15x^4-146x^3+235x^2+352x+84=0$

$(x-7)(3x+2)(5x^2-17x-6)=0\implies\boxed{x=-\dfrac23\text{ or }x=7}$

(again, omit the solutions that would give a negative length for either AB or AD)

7 0

3 years ago