Answer:
Ix - 950°C I ≤ 250°C
Step-by-step explanation:
We are told that the temperature may vary from 700 degrees Celsius to 1200 degrees Celsius.
And that this temperature is x.
This means that the minimum value of x is 700°C while maximum of x is 1200 °C
Let's find the average of the two temperature limits given:
x_avg = (700 + 1200)/2 =
x_avg = 1900/2
x_avg = 950 °C
Now let's find the distance between the average and either maximum or minimum.
d_avg = (1200 - 700)/2
d_avg = 500/2
d_avg = 250°C.
Now absolute value equation will be in the form of;
Ix - x_avgI ≤ d_avg
Thus;
Ix - 950°C I ≤ 250°C
Answer:
We must solve 3/5 x 3/5.
3/5 x 3/5 = 0.36
The units we'll use is because units are the unt we're given, and it is squared because it is the area of a shape.
Your final answer is 0.36
X/3 +4 = 5+x/6
6(x/3 +4 = 5+x/6)
2x+ 24 = 30 +x
x= 6
Ok so what is the question..... question in detail
