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jolli1 [7]
3 years ago
14

Find the other endpoint of the line segment with the given endpoint and midpoint. Endpoint: (9,8) Midpoint (0,9)​

Mathematics
1 answer:
shepuryov [24]3 years ago
5 0

Answer:

(-9, 10)

Step-by-step explanation:

The location of the midpoint of a line with endpoint at (x_1,y_1) and (x_2,y_2) is given as (x, y). The location of x and y are:

x = \frac{x_1+x_2}{2},y=\frac{y_1+y_2}{2}

Given the endpoint (9,8) and Midpoint (0,9), the location of the other endpoint can be gotten from:

0=\frac{9+x_2}{2}\\ \\9+x_2=0\\\\x_2=-9\\\\Also,9=\frac{8+y_2}{2}\\ \\8+y_2=18\\\\y_2=18-8\\\\y_2=10

Hence the endpoint is at (x2, y2) which is at (-9, 10)

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What is the largest fraction 3/4 7/8 8/10 7/9?
Tems11 [23]

Answer:

7/8 ths

Step-by-step explanation:

3 divided by 4 is .75

* 7 divided by 8 is .875

8 divided by 10 is .80

7 divided by 9 is .77

If you divide the fractions you can compare the values and the highest value is your largest fraction.

7 0
3 years ago
Express 0.8342 as a fraction
prohojiy [21]
<span>0.8342 = <span>4171/5000
</span></span><span><span>.................

</span></span>
5 0
3 years ago
Find the length of the arc on a circle of radius r intercepted by a central angle 0. Round answer to
mario62 [17]

Answer:

yes

Step-by-step explanation:

soory i need points

3 0
2 years ago
How are slope 1 and slope 2 related?
Diano4ka-milaya [45]
The answer is B. Adjacent angles. They both have a meeting point and don't overlap.
The answer isn't A. because both angles don't add up to 90°.
The answer isn't C. because both angles aren't 90°.
The answer isn't D. because both angles don't add up to 180°.

Hope this helps! :)

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6 0
3 years ago
Jackie scored 81 and 87 on her first two quizzes . Write and solve a compound inequality to find the possible values for a third
asambeis [7]

Answer:

The third score must be larger than or equal to 72, and smaller than or equal 87

Step-by-step explanation:

Let's name "x" the third quiz score for which we need to find the values to get the desired average.

Recalling that average grade for three quizzes is the addition of the values on each, divided by the number of quizzes (3), we have the following expression for the average:

average=\frac{81+87+x}{3}

SInce we want this average to be in between 80 and 85, we write the following double inequality using the symbols that include equal sign since we are requested the average to be between 80 and 85 inclusive:

80\leq average\leq 85\\80\leq \frac{81+87+x}{3} \leq 85\\80\leq \frac{168+x}{3} \leq 85

Now we can proceed to solve for the unknown "x" treating each inaquality at a time:

80\leq \frac{168+x}{3}\\3*80\leq 168+x\\240\leq 168+x\\240-168\leq x\\72\leq x

This inequality tells us that the score in the third quiz must be larger than or equal to 72.

Now we study the second inequality to find the other restriction on "x":

\frac{168+x}{3} \leq 85\\168+x\leq 85 *3\\168+x\leq 255\\x\leq 255-168\\x\leq 87

This ine72\leq x} \leq 87quality tells us that the score in the third test must be smaller than or equal to 87 to reach the goal.

Therefore to obtained the requested condition for the average, the third score must be larger than or equal to 72, and smaller than or equal 87:

4 0
3 years ago
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