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3 years ago

Find the other endpoint of the line segment with the given endpoint and midpoint. Endpoint: (9,8) Midpoint (0,9)

Mathematics

1 answer:

shepuryov [24]3 years ago

5 0

Answer:

(-9, 10)

Step-by-step explanation:

The location of the midpoint of a line with endpoint at ( $x_1,y_1$ ) and ( $x_2,y_2$ ) is given as (x, y). The location of x and y are:

$x = \frac{x_1+x_2}{2},y=\frac{y_1+y_2}{2}$

Given the endpoint (9,8) and Midpoint (0,9), the location of the other endpoint can be gotten from:

$0=\frac{9+x_2}{2}\\ \\9+x_2=0\\\\x_2=-9\\\\Also,9=\frac{8+y_2}{2}\\ \\8+y_2=18\\\\y_2=18-8\\\\y_2=10$

Hence the endpoint is at (x2, y2) which is at (-9, 10)

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2 years ago

A recent study of 26 city residents showed that the time they had lived at their present address has a mean of 10.3 years with t

svetlana [45]

Answer:

The 95% confidence interval is $9.15< \mu < 11.45$

Step-by-step explanation:

From the question we are told that

The sample size is n = 26

The mean is $\= x = 10.3$

The standard deviation is $s = 3$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E = 1.96 * \frac{3}{\sqrt{26} }$

=> $E = 1.1532$

Generally 95% confidence interval is mathematically represented as

$\= x -E < \mu < \=x +E$

=> $10.3 -1.1532 < \mu < 10.3 + 1.1532$

=> $9.15< \mu < 11.45$

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2 years ago

Can any math genius help me with this

vovangra [49]

Here's my working for 1) You need to find the exterior angle, then divide by 360 to find the number of sides:

Applying these steps : 

180 (Interior Angles) - 162 = 18 (Exterior angle)

360 ÷ 18 is 20 sides 

For 2)

Its the same method, so apply the steps:

180 - 175 = 5

360 ÷ 5 = 72 sides 

Hope it helps! :) 

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2 years ago

Find the other endpoint of the line segment with the given endpoint and midpoint. Endpoint: (9,8) Midpoint (0,9)​

Find the other endpoint of the line segment with the given endpoint and midpoint. Endpoint: (9,8) Midpoint (0,9)