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lutik1710 [3]
3 years ago
14

Edison has a sales job and receives $45,448 as his annual pay, plus commission. His company pays him a commission of 15% on his

total sales. If he makes sales of $25,000 in the first 3 months, how much will he be paid for those 3 months?
Mathematics
1 answer:
11111nata11111 [884]3 years ago
4 0

Answer:

Edison will be paid $15,112 for 3 months

Step-by-step explanation:

Edison receives an annual fixed pay = $45,448.

Monthly pay  = 45,448/12 = $3787.33

3-month salary = $3787.33 *3 = $11.362

Commission = 15%

Total sale = $25,000 for the first 3 months.

Commission amount = 25,000*0.15 = $3750

Therefore, total pay that Edison received during first 3 months= salary + commission

= $11,362 + $3750

= $15,112

Thank you.


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0/1<br> (-7x2 + 2x – 9) - (2 + 9x2 + 3x)<br> 7<br> 8<br> 9
loris [4]
The answer is 9 I believe
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2 years ago
A jar of peanut butter contains 454 g with a standard deviation of 10.2 g. Find the probability that a jar contains more than 46
Fofino [41]

Answer:

The probability that a jar contains more than 466 g is 0.119.

Step-by-step explanation:

We are given that a jar of peanut butter contains a mean of 454 g with a standard deviation of 10.2 g.

Let X = <u><em>Amount of peanut butter in a jar</em></u>

The z-score probability distribution for the normal distribution is given by;

                                Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean = 454 g

           \sigma = standard deviation = 10.2 g

So, X ~ Normal(\mu=454 , \sigma^{2} = 10.2^{2})

Now, the probability that a jar contains more than 466 g is given by = P(X > 466 g)

            P(X > 466 g) = P( \frac{X-\mu}{\sigma} > \frac{466-454}{10.2} ) = P(Z > 1.18) = 1 - P(Z \leq 1.18)

                                                                  = 1 - 0.881 = <u>0.119</u>

The above probability is calculated by looking at the value of x = 1.18 in the z table which has an area of 0.881.

4 0
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Please help!!!!!!!!!
kotykmax [81]

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8 0
3 years ago
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After being treated with chemotherapy, the radius of the tumor decreased by 23%. What is the corresponding percentage decrease i
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Answer:

The volume of the tumor experimented a decrease of 54.34 percent.

Step-by-step explanation:

Let suppose that tumor has an spherical geometry, whose volume (V) is calculated by:

V = \frac{4\pi}{3}\cdot R^{3}

Where R is the radius of the tumor.

The percentage decrease in the volume of the tumor (\%V) is expressed by:

\%V = \frac{\Delta V}{V_{o}} \times 100\,\%

Where:

\Delta V - Absolute decrease in the volume of the tumor.

V_{o} - Initial volume of the tumor.

The absolute decrease in the volume of the tumor is:

\Delta V = V_{o}-V_{f}

\Delta V = \frac{4\pi}{3}\cdot (R_{f}^{3}-R_{o}^{3})

The percentage decrease is finally simplified:

\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%

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