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NemiM [27]
2 years ago
9

What is the distance between (4, 3) and (7, 3)?

Mathematics
2 answers:
ZanzabumX [31]2 years ago
7 0
There is a difference of 3 on the x axis
iris [78.8K]2 years ago
4 0
For this one 3 is the distance between you’re coordinate points.
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A group of friends went to the movies together. The ticket price was $9.00 per
zhuklara [117]

Answer:

4 people

Step-by-step explanation:

9-2= $7

28/7 = 4

3 0
3 years ago
Please help me to prove this!<br>I need is no.(c). So, please help me do it.<br>​
zloy xaker [14]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = 90°                  → A + B = 90° - C

                                                     → C = 90° - (A + B)

Use the Double Angle Identity:      cos 2A = 1 - 2 sin² A

                                                       → sin² A = (1 - cos 2A)/2

Use Sum to Product Identity: cos A + cos B = 2 cos [(A + B)/2] · cos [(A - B)/2]

Use the Product to Sum Identity: cos (A - B) - cos (A + B) = 2 sin A · sin B

Use the Cofunction Identities:      cos (90° - A) = sin A

                                                       sin (90° - A) = cos A

<u>Proof LHS → RHS:</u>

LHS:                       sin² A + sin² B + sin² C

\text{Double Angle:}\qquad \dfrac{1-\cos 2A}{2}+\dfrac{1-\cos 2B}{2}+\sin^2 C\\\\\\.\qquad \qquad \qquad =\dfrac{1}{2}\bigg(2-\cos 2A-\cos 2B\bigg)+\sin^2 C\\\\\\.\qquad \qquad \qquad =1-\dfrac{1}{2}\bigg(\cos 2A+\cos 2B\bigg)+\sin^2 C

\text{Sum to Product:}\quad 1-\dfrac{1}{2}\bigg[2\cos \bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A-2B}{2}\bigg)\bigg]+\sin^2 C\\\\\\.\qquad \qquad \qquad =1-\cos (A+B)\cdot \cos (A-B)+\sin^2 C

Given:                1 - cos (90° - C) · cos (A - B) + sin² C

Cofunction:       1 - sin C · cos (A - B) + sin² C

Factor:               1 - sin C [cos (A - B) + sin C]

Given:                1 - sin C[cos (A - B) - sin (90° - (A + B))]

Cofunction:       1 - sin C[cos (A - B) - cos (A + B)]

Sum to Product:       1 - sin C [2 sin A · sin B]

                            = 1 - 2 sin A · sin B · sin C

LHS = RHS: 1 - 2 sin A · sin B · sin C = 1 - 2 sin A · sin B · sin C   \checkmark

6 0
3 years ago
Which of the following are exterior angles? Check all that apply.
Romashka [77]

[|] Answer [|]

<u><em>6, 5, 4</em></u>

<u><em></em></u>

[|] Explanation [|]

<em>Exterior Angles:</em>

<u><em>Angles facing outward on a triangle</em></u>

Angles 6, 5 and

4 are not inside the main triangle. They are wide open. <u><em>Exterior simply means the outside of something.</em></u> Angles 6, 5 and 4 are the outside angles to the main triangle.

<u><em>_[|] Eclipsed [|] _</em></u>

8 0
3 years ago
During the Indy 500, the winning car traveled at an average constant speed of 232 miles per hour. The equation d = 232t represen
Mars2501 [29]

Answer:

The car traveled 232 miles in one hour.

Step-by-step explanation:

<em>232 miles per hour.</em>

<em />

7 0
4 years ago
Plz help me .....simplify the ratio of 0,0064kg to 32 grams<br>​
Degger [83]

9514 1404 393

Answer:

  1/5

Step-by-step explanation:

1 kg = 1000 g so your ratio is ...

  \dfrac{0.0064\text{ kg}}{32\text{ g}}=\dfrac{0.0064\cdot1000\text{ g}}{32\text{ g}}=\dfrac{6.4}{32}=\boxed{\dfrac{1}{5}}

4 0
3 years ago
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