Answer:
Total reduction after 2 years =
rupees
Step-by-step explanation:
Current price of a machine
= 45,000 rupees
Rate of depreciation (r) = 20%
Time (t) = 2 years
Price after 2 years = ![P_0(1-\frac{r}{100} )^t](https://tex.z-dn.net/?f=P_0%281-%5Cfrac%7Br%7D%7B100%7D%20%29%5Et)
![=45000(1-\frac{20}{100})^2 \\=45000(1-\frac{1}{5})^2\\ =45000(\frac{4}{5})^2\\ =45000(\frac{16}{25})](https://tex.z-dn.net/?f=%3D45000%281-%5Cfrac%7B20%7D%7B100%7D%29%5E2%20%5C%5C%3D45000%281-%5Cfrac%7B1%7D%7B5%7D%29%5E2%5C%5C%20%3D45000%28%5Cfrac%7B4%7D%7B5%7D%29%5E2%5C%5C%20%3D45000%28%5Cfrac%7B16%7D%7B25%7D%29)
rupees
Total reduction after 2 years =
rupees
Working:
Area of the rectangle= 12 x 4 =
48cm^2Area of the semicircles=
![\pi](https://tex.z-dn.net/?f=%20%5Cpi)
x 2² =
12.56cm^2
48+12.56= 60.56
Answer: 60.56cm²
Hi,
if growth continue to the same rate, meaning +25% more every year, then B is the answer :
100 (1.25)^t
Answer:
3p = 7.50 its something like that but hoped this helped
Step-by-step explanation
7.50 divided by 3
2.50
p= 2.50