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nalin [4]
3 years ago
10

What is the value of 7x2 + 2x when x = 3

Mathematics
2 answers:
telo118 [61]3 years ago
6 0
7x2+2x
7(3)2+2(3)
7(9)+6
63+6
69 so the answer is 69
Sophie [7]3 years ago
3 0

Answer:

The answer is 20

Step-by-step explanation:

2x=6 and then 7x2=14 then 14+6=20

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I need help pllllzzzzz help help
konstantin123 [22]

Answer:

a = 84/14

Step-by-step explanation:

The next step you would divide by 14 to get a=6 so I think the program wants you to input a = 84/14

4 0
2 years ago
Factor the expression.
grigory [225]
Hey!

First, let's write the problem,
4r^2-64
Factor out the common term, which is 4,
=4\left(r^2-16\right)
Then, let's factor this part: r^2-16
We are going to factor it using the difference of squares rule.
=\left(r+4\right)\left(r-4\right)
Our final factored answer would be,
=4\left(r+4\right)\left(r-4\right)

Thanks!
-TetraFish
8 0
3 years ago
Read 2 more answers
3x + 4y = 24 => X+y=?
ikadub [295]

x + y = x / 4 + 6

because you divide them

8 0
3 years ago
The diagram shows a 5 cm x 5 cm x 5 cm cube.
mylen [45]

Answer:

~8.66cm

Step-by-step explanation:

The length of a diagonal of a rectangular of sides a and b is

\sqrt{a^2+b^2}

in a cube, we can start by computing the diagonal of a rectangular side/wall containing A and then the diagonal of the rectangle formed by that diagonal and the edge leading to A. If the cube has sides a, b and c, we infer that the length is:

\sqrt{\sqrt{a^2+b^2}^2 + c^2} = \sqrt{a^2+b^2+c^2}

Using this reasoning, we can prove that in a n-dimensional space, the length of the longest diagonal of a hypercube of edge lengths a_1, a_2, a_3, \ldots, a_n is

\sqrt{a_1^2 + a_2^2 + a_3^2 + \ldots + a_n^2}

So the solution here is

\sqrt{(5cm)^2 + (5cm)^2 + (5cm)^2} = \sqrt{75cm^2} = 5\sqrt{3cm^2} \approx 5\cdot 1.732cm = 8.66cm

5 0
2 years ago
Read 2 more answers
Hii please help i’ll give brainliest
elena-14-01-66 [18.8K]
C: Bc 3 * c = 3c (plus 7 more) = 7+3c
8 0
2 years ago
Read 2 more answers
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