The answer to this question mark will do it all in a few weeks to make it happen again this week at the end
Answer:
X is 83
Step-by-step explanation:
Subtract 180 because thats what all of them eaqual and you subtract 97 from 180
Answer:
The actual SAT-M score marking the 98th percentile is 735.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Find the actual SAT-M score marking the 98th percentile
This is X when Z has a pvalue of 0.98. So it is X when Z = 2.054. So
Answer:
90 + 6
Step-by-step explanation:
90 + 6 = 96
<u>ALTERNATIVE</u><u>:</u>
96 - 6 = 90
-2y + 5z = -3
y = -5x - 4z - 5
x = 4z + 4
-2(-5(4z + 4) - 4z - 5) + 5z = -3
-2(-20z - 20 - 4z - 5) + 5z = -3
-2(-20z - 4z - 20 - 5) + 5z = -3
-2(-24z - 25) = -3
48z + 50 = -3
<u> - 50 - 50</u>
<u>48z</u> = <u>-53</u>
48 48
z = -1⁵/₄₈
x = 4(-1⁵/₄₈) + 4
x = -4⁵/₁₂ + 4
x = ⁵/₁₂
y = -5(⁵/₁₂) - 4(-1⁵/₄₈) - 5
y = -2¹/₂ + 4⁵/₁₂ - 5
y = 1¹¹/₁₂ - 5
y = -3¹/₂
(x, y, z) = (⁵/₁₂, -3¹/₂, -1⁵/₄₈)