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Len [333]
3 years ago
13

You are planning to plant a triangular garden in your backyard, as shown. You plan to put up a fence around the garden to keep o

ut animals. Find the length of fencing you need to the nearest meter.​

Mathematics
1 answer:
Drupady [299]3 years ago
6 0

Answer:

24 m

Step-by-step explanation:

The lenght of fencing needed is the sum of all sides the triangular garden represented on the coordinate grid.

The lenght of the triangular garden = 16 - 10 = 6 m

Lenght of the height = 8 - 0 = 8 m

Lenght of the hypotenuse can be calculated using coordinates of the two vertices of the ∆ that forms the hypotenuse lenght and also using the distance formula.

Coordinates of the two vertices = (10, 0) and (16, 8).

distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

(10, 0) = (x_1, y_1)

(16, 8) = (x_2, y_2)

d = \sqrt{(16 - 10)^2 + (8 - 0)^2}

d = \sqrt{(6)^2 + (8)^2}

d = \sqrt{36 + 64} = \sqrt{100}

d = 10

Length of fencing = 6 + 8 + 10 = 24 m

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Answer:

Step-by-step explanation:

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1 year ago
Find - 2 2/6 + (5/6)
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3 years ago
Which shows 0.23 repeated as a fraction.<br> A. 2/33 <br> B. 7/33 <br> C. 23/99 <br> D. 7/30
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2 years ago
A manufacturer of matches randomly and independently puts 23 matches in each box of matches produced. The company knows that one
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Answer:

0.9855 or 98.55%.

Step-by-step explanation:

The probability of each individual match being flawed is p = 0.008. The probability that a matchbox will have one or fewer matches with a flaw is the same as the probability of a matchbox having exactly one or exactly zero matches with a flaw:

P(X\leq 1)=P(X=0)+P(X=1)\\P(X\leq 1)=(1-p)^{23}+23*(1-p)^{23-1}*p\\P(X\leq 1)=(1-0.008)^{23}+23*(1-0.008)^{23-1}*0.008\\P(X\leq 1)=0.8313+0.1542\\P(X\leq 1)=0.9855

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3 years ago
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