All categories

3 years ago

What are the slope and the y-intercept of the linear function that is represented by the table?

2 answers:

4 0

1) m = -2 & y = 6

y = mx + b
y = -2x + 6

2) m = -2 & y = 12
y = -2x + 12

3) m = 2 & y = 6
y = 2x + 6

4) m = 2 & y = 12
y = 2x + 12

seropon [69]3 years ago

3 0

Answer:

The answer is the option 2

The slope is $-2$ , and the y-intercept is $12$

Step-by-step explanation:

we have

$A(-3,18),B(0,12),C(3,6),D(6,0)$

Step 1

Find the slope

we know that

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

$A(-3,18),B(0,12)$

Substitute the values

$m=\frac{12-18}{0+3}$

$m=\frac{-6}{3}$

$m=-2$

Step 2

Find they-intercept

we know that

The y-intercept is the value of y when the value of x is equal to zero

therefore

The y-intercept is the point $B(0,12)$

You might be interested in

During a snowstorm, the temperature drops from 0°F to -10°F in 2 hours. On average,by how many degrees is the temperature changi

masha68 [24]

Answer:

-5°F

Step-by-step explanation:

As, in 2 hrs = - 10°F

For 1 hr = - 10°F/2 = - 5°F

So, answer = - 5°F

6 0

2 years ago

A small military base housing 1,000 troops, each of whom is susceptible to a certain virus infection. Assuming that during the c

slava [35]

Answer:

$I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

Step-by-step explanation:

The rate of infection is jointly proportional to the number of infected troopers and the number of non-infected ones. It can be expressed as follows:

$\frac{dI}{dt}=a*I*(1000-I)$

Rearranging and integrating

$\frac{dI}{dt}=a*I*(1000-I)\\\\\frac{dI}{I*(1000-I)}=a*dt\\\\\int\frac{dI}{I*(1000-I)}=\int a*dt\\\\-\frac{ln(1000/I-1)}{1000}+C=a*t$

At the initial breakout (t=0) there was one trooper infected (I=1)

$-\frac{ln(1000/1-1)}{1000}+C=0\\\\-0,006906755+C=0\\\\C=0,006906755$

In two days (t=2) there were 5 troopers infected

$-\frac{ln(1000/5-1)}{1000}+0,006906755=a*2\\\\-0,005293305+0,006906755=2*a\\a = 0,00161345 / 2 = 0,000806725$

Rearranging, we can model the number of infected troops (I) as

$-\frac{ln(1000/I-1)}{1000}+0,006906755=0,000806725*t\\\\-\frac{ln(1000/I-1)}{1000}=0,000806725*t-0,006906755\\-ln(1000/I-1)=0,806725*t-0.6906755\\\\\frac{1000}{I}-1=exp^{0,806725*t-0.6906755} \\\\\frac{1000}{I}=exp^{0,806725*t-0.6906755}+1\\\\I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$