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Brums [2.3K]
3 years ago
5

Phyllis paid $408 for new wall-to-wall carpeting in her living room. The carpeting was $12 per square yard, plus a $120 installa

tion charge. How many square yards did she buy?
A. 26 sq yd


B. 34 sq yd


C. 44 sq yd


D. 24 sq yd
Mathematics
1 answer:
kipiarov [429]3 years ago
3 0
.)26

y=12x+120

y=12(26)+120

y=312+120

y=432 (No)

B.)34

y=12x+120

y=12(34)+120

y=408+120

y=528 (No)

C.)44

y=12(44)+120

y=528+120

y=648 (No)

D.)24

y=12x+120

y=12(24)+120

y=288+120

y=408 (Yes)

The other way is setting it equal to...

12x+120=408

Isolate the variable...

12x+120=408
       -120   -120

12x=288

x=24
Thus (D) is you answer!

Hope this helps!
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The trapezoid consists of a triangle and a parallelogram. The area of the trapezoid is 48 square feet. Find the length of the ba
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3 years ago
In a class of 25 students, the following test scores were obtained:
marta [7]

Answer:

Step-by-step explanation:

Firstly,we need to find the mean, median and mode to enable us know the type of distribution it exhibit.

Mode-data with the highest frequency that is data that has the highest repetition which is 59.

Median-the middle data which is 75.

Mean-average of the data that is addition of the data divided by 25 which gives 75.4 approximately equals to 75

Distribution is unimodal symmetric if it has one clear peak(one mode) and mean = median , so Option A is right

Distribution is skewed left if the mean is less than median and the mode is less than the median that is mean is less than the median, and they are both less than the mode. So option B is wrong.

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5 0
4 years ago
Question 1 ( point) A 64g sample of Germanium-66 is left undisturbed for 12.5 hours. At the end of that period, only 2.0g remain
iVinArrow [24]

Answer:

2.5 half-lives

Step-by-step explanation:

Find t_{h} in N(t)=N_{0}e^{-kt} given N(t) = 2, N_{0} =64,t=\frac{25}{2}

N(t) is the amount after the time t, N_0 `is the initial amount, t_{h} is the half-life

We know that after half-life there will be twice less the initial quantity:

N(t_{h})=\frac{N_{0} }{2}=N_{0}e^{kt_{h} }.

Simplifying gives \frac{1}{2} =e^{-kt_h} or k = -\frac{In(\frac{1}{2}) }{t_{h} }  .

Plugging this into the initial equation, we obtain that N(t)=N_{0}e^\frac{In(\frac{1}{2}) }{t_{h} }or N(t)= N_{0} (\frac{1}{2})^\frac{t}{t_h}.

Finally, just plug in the given values and find the unknown one.

From 2=64(\frac{1}{2})^\frac{\frac{25}{2} }{t_h}, we have that t_h = \frac{25 In (2)}{2 In (32)\\}

So you should get: t_{h} =\frac{25 In (2)}{2 In (32)\\}=2.5.

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5 0
3 years ago
Read 2 more answers
(a+b+c)(d+e+f)(a+b+c)(d+e+f)(a+ b+ c) <br> ( d+e+ f)
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Hi the expanded form is

d^3 a^3 + e^3 a^3 + f^3 a^3 + 3 d e^2 a^3 + 3 d f^2 a^3 + 3 e f^2 a^3 + 3 d^2 e a^3 + 3 d^2 f a^3 + 3 e^2 f a^3 + 6 d e f a^3 \\+ 3 b d^3 a^2 + 3 c d^3 a^2 \\+ 3 b e^3 a^2 + 3 c e^3 a^2 + 3 b f^3 a^2 \\+ 3 c f^3 a^2 + 9 b d e^2 a^2 + 9 c d e^2 a^2 + 9 b d f^2 a^2 + 9 c d f^2 a^2\\ + 9 b e f^2 a^2 + 9 c e f^2 a^2 + 9 b d^2 e a^2 + 9 c d^2 e a^2 + 9 b d^2 f a^2 + 9 c d^2 f a^2 \\+ 9 b e^2 f a^2 + 9 c e^2 f a^2 + 18 b d e f a^2

+ 18 c d e f a^2 + 3 b^2 d^3 a + 3 c^2 d^3 a \\+ 6 b c d^3 a + 3 b^2 e^3 a + 3 c^2 e^3 a + 6 b c e^3 a + 3 b^2 f^3 a \\+ 3 c^2 f^3 a + 6 b c f^3 a + 9 b^2 d e^2 a \\+ 9 c^2 d e^2 a + 18 b c d e^2 a + 9 b^2 d f^2 a\\ + 9 c^2 d f^2 a + 18 b c d f^2 a + 9 b^2 e f^2 a + 9 c^2 e f^2 a + 18 b c e f^2 a + 9 b^2 d^2 e a \\+ 9 c^2 d^2 e a + 18 b c d^2 e a + 9 b^2 d^2 f a + 9 c^2 d^2 f a + 18 b c d^2 f a \\+ 9 b^2 e^2 f a + 9 c^2 e^2 f a + 18 b c e^2 f a

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3 years ago
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