Solution:
Number of times a die is rolled = 20
1 - 3=A
2 - 5=B
3 - 4=C
4 - 2=D
5 - 3=E
6 - 3=F
Total number of arrangements of outcomes , when a dice is rolled 20 times given that 1 appear 3 times, 2 appears 5 times, 3 appear 4 times, 4 appear 2 times , 5 appear three times, and 6 appear 3 times
= Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes
= 6! × [ 3! × 5! × 4!×2!×3!×3!]
= 720 × 6×120×24×72→→[Keep in Mind →n!= n (n-1)(n-2)(n-3)........1]
= 895795200 Ways
Solving the expressions 
we get 
Step-by-step explanation:
We need to Solve the expression:
Solving:
Applying exponent rule: 
Another exponent rule says: 
So, solving the expressions we get
Keywords: Solving Exponents
Learn more about Solving Exponents at:
#learnwithBrainly
Hey!
Let's walk through this together.
Possible Answers: {5, 7, 9, 11, 13}
Let's start with 5.
5-4<8
1<8
So, 5 is CORRECT.
Next, 7.
7-4<8
3<8
So, 7 is CORRECT.
Next, 9.
9-4<8
5<8
So, 9 is CORRECT.
Next, 11.
11-4<8
7<8
So, 11 is CORRECT.
Last, 13.
13-4<8
11<8
So, 13 is INCORRECT.
Your answers are: {5,7,9,11}
So D.
Hope this helps!
<h2><em>
~~~PicklePoppers~~~</em></h2>
Answer:The first one
Step-by-step explanation:
V rectangular prism = Area of the base *5
