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Luba_88 [7]
3 years ago
10

Write a linear function f with the values f(0)=-1 and f(2)=-5

Mathematics
1 answer:
ruslelena [56]3 years ago
4 0
F(x) = -2x -1
or 
y = -2x-1
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How to write 6,858.026 in expanded form
tia_tia [17]
6,000.000+800.000+50.000+8.000+0.000+0.20+0.6
4 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP f(x) = x2 What is g(x)?
vfiekz [6]

Answer:

c. g(x) = 4x^2

Step-by-step explanation:

From a first glance, since g(x), is skinnier than f(x), meaning that it is increasing faster, so I know that I can eliminate options A & B since the coefficient on x needs to be greater than 1.

We can then look and see that g(1) = 4 as shown by the point given to us on the graph.

To find the right answer we can find g(1) for options C & D and whichever one matches the point on the graph is our correct answer. e

Option C:

once we plug in 1 for x, our equation looks like

4(1)^2.

1^2 = 1, and 4(1) = 4,

so g(1) = 4. and our point is (1,4).

This is the same as the graph so this is the CORRECT answer.

If you want to double check, you can still find g(1) for option D and verify that it is the WRONG answer.

Option D:

once we plug in 1 for x, our equation looks like

16(1)^2

1^2 = 1, and 16(1) = 16,

so g(1) = 16. and our point is (1,16).

This is different than the graph so this is the WRONG answer.

3 0
3 years ago
Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

  • J(2;5); K(1;1)

             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0
3 years ago
Read 2 more answers
Use quadratic regression to find
Rashid [163]

The quadratic equation is given by:

y = 3x² + 10x - 8

The standard equation of a parabola is given by:

y = ax² + bx + c

Where a, b, c are constants

At point (4, 80):

80 = a(4)² + b(4) + c

16a + 4b + c = 80     (1)

At point (-3, -11):

-11 = a(-3)² + b(-3) + c

9a - 3b + c = -11     (2)

At point (-1, -15):

-15 = a(-1)² + b(-1) + c

a - b + c = -15     (3)

Solving equations 1, 2 and 3 simultaneously gives:

a = 3, b = 10, c = -8

Therefore the quadratic equation becomes:

y = 3x² + 10x - 8

Find out more on quadratic equation at: brainly.com/question/1214333

8 0
2 years ago
28 - 6(2x + 4) = 124​
Iteru [2.4K]

Answer: x = -12 is the correct answer

Step-by-step explanation: the moderator that deleted this if is so wrong then just tell me why is wrong if you are so smart.

5 0
3 years ago
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