1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
In-s [12.5K]
3 years ago
13

What expression is equivalent to (4y^2-3) (4y+3)

Mathematics
1 answer:
Naya [18.7K]3 years ago
4 0

Answer:

Step-by-step explanation:

Just use the distributive property.

(4y^2-3)(4y+3)

= 4y^2(4y+3) - 3(4y+3)

= 16y^3 + 12y^2 - 12y - 9

You might be interested in
-2(3/8)+6/7<br> Simplify
nikitadnepr [17]
The answer should be -3/28
6 0
2 years ago
Read 2 more answers
Simplify this expression 9*(4*3)^2
Lisa [10]
Answers: 11,664



Explanation: idk I used Photomath
3 0
2 years ago
Graph 4x minus 2y equals 10
inna [77]
Put it on the graph as 2xy=10!
8 0
2 years ago
How to simplify the square root of 9/245
lana66690 [7]
<span><span>the exact answer is 3 over
 <span>5√</span> </span>35</span>
8 0
3 years ago
Heyy can you please help me posted picture of question
True [87]
\bigg(  \frac{4}{5} \bigg)^6 =  \dfrac{4^6}{5^6}
8 0
3 years ago
Read 2 more answers
Other questions:
  • Evaluate the numerical expression of 27 + 5 × 6
    6·1 answer
  • Write at least 5 names for 1/4
    11·1 answer
  • Does this really works
    5·1 answer
  • Add.
    6·2 answers
  • The table below shows the values of y for different values of x:
    5·1 answer
  • I need help on this question
    6·1 answer
  • The bacteria in an old piece of cheese is growing at a rate that can be modeled by y = 280 • 2x. Determine which number represen
    5·1 answer
  • This is so confusing all of it makes no sense
    7·2 answers
  • HELP ME PLEASEEEEEEEEEEEEE
    10·1 answer
  • Which of the following algebraic equations models the English sentence, a number decreased by two is equal to
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!