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MAVERICK [17]
3 years ago
15

In an experiment, the one variable that is changed by the person doing the experiment is called the Question 2 options: controll

ed variable testing variable independent variable dependent variable
Mathematics
1 answer:
Ad libitum [116K]3 years ago
5 0

Answer: Independent Variable

Step-by-step explanation:

The independent (or manipulated) variable is something that the experimenter purposely changes or varies over the course of the investigation. The dependent (or responding) variable is the one that is observed and likely changes in response to the independent variable.

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Please answer my questions without links lol
guapka [62]

Answer:

Did you got my answer

if you don't then you can ask again as I will try my best

5 0
3 years ago
it costs $12 to attend a golf clinic with a local pro. Buckets of balls for practice during the clinic costs $3 each. How many b
goldfiish [28.3K]

Answer: If you take out the price of the golf clinic with a local pro, you could buy 6 buckets.

Step-by-step explanation:

4 0
3 years ago
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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!<br><br> Factor.<br><br> 11x^2 + 35x + 6
8_murik_8 [283]

The answer would be (11x+2)(x+3).

3 0
3 years ago
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Expand each expression
matrenka [14]

Answer:

Option B - \ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x

Step-by-step explanation:

Given : Expression \ln(\frac{4y^5}{x^2})

To find : Expand each expression ?

Solution :

Using logarithmic properties,

\ln (\frac{A}{B})=\frac{\ln A}{\ln B}=\ln A-\ln B

and \ln (AB)=\ln A+\ln B

Here, A=4y^5 and B=x^2

\ln(\frac{4y^5}{x^2})=\frac{\ln 4y^5}{\ln x^2}

\ln(\frac{4y^5}{x^2})=\ln 4y^5-\ln x^2

\ln(\frac{4y^5}{x^2})=\ln 4+\ln y^5-\ln x^2

Using logarithmic property, \logx^a=a\log x

\ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x

Therefore, option B is correct.

3 0
2 years ago
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Carter misses 25% of the free throws he attempts in a season. How many total free
Inga [223]

Answer:

so 25% of 63

63x25:100

15,75=

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Step-by-step explanation:

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2 years ago
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