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3 years ago

A set of data points has a line of best fit of y = –0.2x + 1.9. What is the residual for the point (5, 1)?

1 answer:

3 0

<span>A. 0.1
The residual is the difference between the observed value and the predicted value for a data point. You obtain it by subtracting the predicted value from the observed value. So the predicted value is: y = -0.2x + 1.9 y = -0.2*5 + 1.9 y = -1 + 1.9 y = 0.9 Therefore the residual is: r = 1 - 0.9 r = 0.1 And the value of 0.1 matches option "A".</span>

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Find the six trig function values of the angle 240*Show all work, do not use calculator

-BARSIC- [3]

Solution:

Given:

$240^0$

To get sin 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, sin 240 will be negative.

$sin240^0=sin(180+60)$

Using the trigonometric identity;

$sin(x+y)=sinx\text{ }cosy+cosx\text{ }siny$

Hence,

$\begin{gathered} sin(180+60)=sin180cos60+cos180sin60 \\ sin180=0 \\ cos60=\frac{1}{2} \\ cos180=-1 \\ sin60=\frac{\sqrt{3}}{2} \\ \\ Thus, \\ sin180cos60+cos180sin60=0(\frac{1}{2})+(-1)(\frac{\sqrt{3}}{2}) \\ sin180cos60+cos180sin60=0-\frac{\sqrt{3}}{2} \\ sin180cos60+cos180sin60=-\frac{\sqrt{3}}{2} \\ \\ Hence, \\ sin240^0=-\frac{\sqrt{3}}{2} \end{gathered}$

To get cos 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, cos 240 will be negative.

$cos240^0=cos(180+60)$

Using the trigonometric identity;

$cos(x+y)=cosx\text{ }cosy-sinx\text{ }siny$

Hence,

$\begin{gathered} cos(180+60)=cos180cos60-sin180sin60 \\ sin180=0 \\ cos60=\frac{1}{2} \\ cos180=-1 \\ sin60=\frac{\sqrt{3}}{2} \\ \\ Thus, \\ cos180cos60-sin180sin60=-1(\frac{1}{2})-0(\frac{\sqrt{3}}{2}) \\ cos180cos60-sin180sin60=-\frac{1}{2}-0 \\ cos180cos60-sin180sin60=-\frac{1}{2} \\ \\ Hence, \\ cos240^0=-\frac{1}{2} \end{gathered}$

To get tan 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, tan 240 will be positive.

$tan240^0=tan(180+60)$

Using the trigonometric identity;

$tan(180+x)=tan\text{ }x$

Hence,

$\begin{gathered} tan(180+60)=tan60 \\ tan60=\sqrt{3} \\ \\ Hence, \\ tan240^0=\sqrt{3} \end{gathered}$

To get cosec 240 degrees:

$\begin{gathered} cosec\text{ }x=\frac{1}{sinx} \\ csc240=\frac{1}{sin240} \\ sin240=-\frac{\sqrt{3}}{2} \\ \\ Hence, \\ csc240=\frac{1}{\frac{-\sqrt{3}}{2}} \\ csc240=-\frac{2}{\sqrt{3}} \\ \\ Rationalizing\text{ the denominator;} \\ csc240=-\frac{2}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}} \\ \\ Thus, \\ csc240^0=-\frac{2\sqrt{3}}{3} \end{gathered}$

To get sec 240 degrees:

$\begin{gathered} sec\text{ }x=\frac{1}{cosx} \\ sec240=\frac{1}{cos240} \\ cos240=-\frac{1}{2} \\ \\ Hence, \\ sec240=\frac{1}{\frac{-1}{2}} \\ sec240=-2 \\ \\ Thus, \\ sec240^0=-2 \end{gathered}$

To get cot 240 degrees:

$\begin{gathered} cot\text{ }x=\frac{1}{tan\text{ }x} \\ cot240=\frac{1}{tan240} \\ tan240=\sqrt{3} \\ \\ Hence, \\ cot240=\frac{1}{\sqrt{3}} \\ \\ Rationalizing\text{ the denominator;} \\ cot240=\frac{1}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}} \\ \\ Thus, \\ cot240^0=\frac{\sqrt{3}}{3} \end{gathered}$

5 0

1 year ago

I am a 2 digit number the sum of my digits is 12. the ones digit is twice the tens digit? who am i?

Bas_tet [7]

Answer:

Step-by-step explanation:

let a be the 1's digit and b the 10's digit, then

a = 2b ← twice the 10's digit, thus

sum = 2b + b = 12, that is

3b = 12 ( divide both sides by 3 )

b = 4

and a = 2b = 2 × 4 = 8

The 2 digit number is 84

5 0

3 years ago

You want to go to graduate school, so you ask your math professor, Dr. Emmy Noether, for a letter of recommendation. You estimat

den301095 [7]

Answer:

$P(G) = 0.69$

$P(S | G) = 0.81$

$P(M|G') = 0.26$

Step-by-step explanation:

From the question we are told the

The probability of getting into getting into graduated school if you receive a strong recommendation is $P(G |S) = 0.80$

The probability of getting into getting into graduated school if you receive a moderately good recommendation is $P(G| M) = 0.60$

The probability of getting into getting into graduated school if you receive a weak recommendation is $P(G|W) = 0.05$

The probability of getting a strong recommendation is $P(S) = 0.7$

The probability of receiving a moderately good recommendation is $P(M) = 0.2$

The probability of receiving a weak recommendation is $P(W) = 0.1$

Generally the probability that you will get into a graduate program is mathematically represented as

$P(G) = P(S) * P(G|S) + P(M) * P(G|M) + P(W) * P(G|W)$

=> $P(G) = 0.7 * 0.8 + 0.2 * 0.6 + 0.1 * 0.05$

=> $P(G) = 0.69$

Generally given that you did receive an offer to attend a graduate program, what is the probability that you received a strong recommendation is mathematically represented as

$P( S|G) = \frac{ P(S) * P(G|S)}{ P(G)}$

=> $P(S|G) = \frac{ 0.7 * 0.8 }{0.69}$

=> $P(S | G) = 0.81$

Generally given that you didn't receive an offer to attend a graduate program the probability that you received a moderately good recommendation is mathematically represented as

$P(M|G') = \frac{ P(M) * (1- P(G|M))}{(1 - P(G))}$