Help me find x, please

The least common multiples

Talja [164]

For second one the answer is 14

8 0

3 years ago

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4. The money in Mrs. Finch’s savings account is earning 1.45% interest. Which number below is greater than 1.45%

makvit [3.9K]

B) 0.019

0.019 = 1.9%

6 0

3 years ago

The table represents the function f (x) = 2 x + 1.

Salsk061 [2.6K]

Answer:

C

Step-by-step explanation:

In the table, we are given the points [ (-3, -5), (2, y), (5, 11), (8, 17) ]

We are given the equation [ f(x) = 2x + 1 ] where 2 = slope and 1 = y intercept.

We need to find the value of "y".

y2-y1/x2-x1

y-(-5)/2-(-3) = 2

y+5/5 = 2

y = 5

Best of Luck!

5 0

3 years ago

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An automated egg carton loader has a 1% probability of cracking an egg, and a customer will complain if more than one egg per do

vaieri [72.5K]

Answer:

a) Binomial distribution B(n=12,p=0.01)

b) P=0.007

c) P=0.999924

d) P=0.366

Step-by-step explanation:

a) The distribution of cracked eggs per dozen should be a binomial distribution B(12,0.01), as it can model 12 independent events.

b) To calculate the probability of having a carton of dozen eggs with more than one cracked egg, we will first calculate the probabilities of having zero or one cracked egg.

$P(k=0)=\binom{12}{0}p^0(1-p)^{12}=1*1*0.99^{12}=1*0.886=0.886\\\\P(k=1)=\binom{12}{1}p^1(1-p)^{11}=12*0.01*0.99^{11}=12*0.01*0.895=0.107$

Then,

$P(k>1)=1-(P(k=0)+P(k=1))=1-(0.886+0.107)=1-0.993=0.007$

c) In this case, the distribution is B(1200,0.01)

$P(k=0)=\binom{1200}{0}p^0(1-p)^{12}=1*1*0.99^{1200}=1* 0.000006 = 0.000006 \\\\ P(k=1)=\binom{1200}{1}p^1(1-p)^{1199}=1200*0.01*0.99^{1199}=1200*0.01* 0.000006 \\\\P(k=1)= 0.00007\\\\\\P(k\leq1)=0.000006+0.000070=0.000076\\\\\\P(k>1)=1-P(k\leq 1)=1-0.000076=0.999924$

d) In this case, the distribution is B(100,0.01)

We can calculate this probability as the probability of having 0 cracked eggs in a batch of 100 eggs.

$P(k=0)=\binom{100}{0}p^0(1-p)^{100}=0.99^{100}=0.366$

5 0

3 years ago

How is adding and subtracting radical expressions similar to adding and subtracting variables ?????

steposvetlana [31]

Answer: To add or subtract radicals, the indices and what is inside the radical (called the radicand) must be exactly the same. If the indices and radicands are the same, then add or subtract the terms in front of each like radical. If the indices or radicands are not the same, then you can not add or subtract the radicals.

4 0

3 years ago

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