In 1 hour, the old machine can produce
widgets.
In 1 hour, the new machine can produce
Answer:
(10, 3)
Step-by-step explanation:
Answer:
Mia spent $1671.00
Step-by-step explanation:
because $1525 + $146 = $1671
Answer:
A) x-1 < n < 3x+5
Step-by-step explanation:
The value of n can range between the sum and difference of the lengths of the other two sides. The sum is ...
(2x +2) +(x +3) = 3x +5
The difference is ...
(2x +2) -(x +3) = x -1
For the purpose of choosing one of these answers, we must assume that the sum is greater than the difference and the value of x is such that x-1 > 0. Using these assumptions, possible values of n are ...
x -1 < n < 3x +5 . . . . . for x > 1
_____
<em>Alternate Solution</em>
The expressions for the given side lengths are both positive when x > -1. In the range -1 < x < 1, we have the condition that 2x+2 ranges from 0 to 4 and x+3 ranges from 2 to 4. That is (x+3) > (2x+2) and possible values of n are ...
lowest: (x+3) -(2x +2) = 1 -x
highest: (x+3) +(2x +2) = 3x +5
So, another possible solution is ...
1-x < n < 3x +5 . . . . . . . for -1 < x < 1
Answer:
an = 52(1.06)^(n-1).
Step-by-step explanation:
After 6 years there are 70 and after 8 years there are 79 so the common ratio can be calculated:
After 6 years : a6 = a1 r^(6 - 1) = a1 r^5 and after 8 it is a1 r^(7) where a1 is the number of raccoons in year 1.
So we have a1 r^7 / a1 r^5
= r^2 = 79/70
r = 1.06 to the nearest hundredth.
To find the number in year 1 we have:
a1 (1.06)^5 = 70
a1 = 70 / (1.06)^5
a1 = 52 raccoons.
So an = 52(1.06)^(n-1).