CXB = 40 degrees
I am not positive but from what I have looked up this is the answer.
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y=1.50
x=0.50
¹
1.50
1.59
______+
3.00
0.50
_____+
<em>3.50</em>
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<em><u>Answer</u></em><em><u>:</u></em><em><u>♡</u></em><em><u>~</u></em></h2>
<em><u>3.50</u></em>
<em><u>HOPE</u></em><em><u> </u></em><em><u>IT</u></em><em><u> </u></em><em><u>HELPSS</u></em>
K = 5 or k = 3
Hope it helps-,-
9w - 7 = 5
9w= 5+7
9w=12
w= 4/3 or 1.33
Let's examine the given function first:
f(x) = x^2 + 1 is the same as f(x) = 1(x-0)^2 + 1.
The vertex of the graph of this function is at (0, 1).
Let x=0 to find the y-intercept: f(0)=0^2+1 = 1; y-int. is at (0,1) (which happens to be the vertex also)
Comparing f(x) = x^2 + 1 to y = x^2, we see that the only difference is that f(x) has a vertical offset of 1. So: Graph y=x^2. Then translate the whole graph UP by 1 unit. That's it. Note (again) that the vertex will be at (0,1), and (0,1) is also the y-intercept.