Question

Find an equation for the line that passes through the points (5,-6) and (-1,-3)​

Answer 1

Answer:

The equation of line passing through given points is 2Y + X + 7 = 0

Step-by-step explanation:

Given points of line as :

(5 , - 6) And ( -1 , - 3)

With this points, we can find the slop of line

So ,Slop ( m ) = $\frac{(y2 - y1 )}{(x2 - x1 )}$

Or,           m    = $\frac{( -3 + 6 )}{( -1 - 5 )}$

Or,           m    = $\frac{( 3 )}{( - 6 )}$

Or, Slop         = $\frac{( -1 )}{( 2 )}$

Now equation of line with this slop and points is :

Y - y1 = m ( X - X1)

Or, Y + 6 = $\frac{( -1 )}{( 2 )}$ ( X - 5 )

Or,  2Y + 12 = - X + 5

∴     2Y + X + 7 = 0

Hence the equation of line passing through given points is 2Y + X + 7 = 0 Answer