Answer:
The Area of a Segment is the area of a sector minus the triangular piece (shown in light blue here). There is a lengthy reason, but the result is a slight modification of the Sector formula: Area of Segment = θ − sin(θ) 2 × r2 (when θ is in radians) Area of Segment = ( θ × π 360 − sin(θ)2 ) × r2 (when θ is in degrees)
Answer:
Around 5.5 square meters
Step-by-step explanation:
You can start by finding the area of the segment. Since the rest of the circle that is not in the segment is 240 degrees, the segment is 120 degrees or a third of the circle. You can therefore find the area of that segment with the formula 
square meters. Now, you need to find the area of the triangle inside the sector. This is more difficult than last time, because it is not a 90 degree angle. However, you can solve this by dividing this triangle into two 30-60-90 triangles, which you know how to find the ratio of sides for. In a 30-60-90 triangle, the hypotenuse is twice the length of the smallest leg, and the larger leg is 
times larger than the smaller leg. In this case, these dimensions are a base of 
for the smaller leg and 
for the larger leg, or the base. Using the triangle area formula and multiplying by 2 (because remember, we divided the big triangle in half), you get 
square meters. Subtracting this from the area of the segment, you get about 5.5 square meters. Hope this helps!
Big town is 5.121 times larger than Small town.
Step-by-step explanation:
Step 1:
In order to determine how much larger Big town's population is to Small town's population is, we need to convert the exponentials into actual numbers.
Small town's population 
Big town's population 
Step 2:
In order to determine how much larger Big town's population is to Small town's population is, we divide Big town's population by Small town's population.
So Big town is 5.121 times larger than Small town.
Answer:
(2,0), (-5,0)
Step-by-step explanation:
I'm not sure if this is correct or not, but going off of what they had for points J and K, I think it's the best answer.
