Answer:
The nth term of the geometric sequence 7, 14, 28, ... is:

Step-by-step explanation:
Given the geometric sequence
7, 14, 28, ...
We know that a geometric sequence has a constant ratio 'r' and is defined by

where a₁ is the first term and r is the common ratio
Computing the ratios of all the adjacent terms

The ratio of all the adjacent terms is the same and equal to

now substituting r = 2 and a₁ = 7 in the nth term


Therefore, the nth term of the geometric sequence 7, 14, 28, ... is:

Written as a power of ten is 256.×10^0 or 2.56×10^1
Answer:
(a) 2ab - a/b
(b) c² + d + 2cd
(c) c + c²
(d) Let x be the number that is 1 greater than b, then x = b + 1
Let y be the number twice as large as b, then y = 2b
Then the quotient of x and y is what we want. This is (b + 1)/2b
(e) pq - 3(p + q)
(f) The quotient of n² and n³ + 5, this is
n²/(n³ + 5)
Answer:
no it is not
Step-by-step explanation:
8 × 1 does not equal 2
D=(S+8)/C
S=DC-8
add 8 to both sides
S+8=DC
divide c from both sides
(S+8)/C=D