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liraira [26]
3 years ago
11

Find mHK please help

Mathematics
1 answer:
Damm [24]3 years ago
4 0

Answer:

66°

Step-by-step explanation:

When a radius(diameter in this case) is perpendicular to a chord, it bisects the chord and the arc formed by the chord. Because of this, we can say mHJ is equal to mKJ. We can write an equation:

mHJ = mKJ

and substitute:

x + 20 = 6x - 45

20 = 5x - 45

65 = 5x

x = 13

mHK is the sum of mHJ and mKJ, we can write mHK as the expression:

x + 20 + 6x - 45

7x - 25

We can substitute x:

7(13) - 25

91 - 25

66°

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5 0
3 years ago
Employees from A and company B receive annual bonuses. What information would you need to test the claim that the difference in
lyudmila [28]

Answer:

1. The required information are

The average annual bonuses, \bar {x}_1 received by employees from company A

The average annual bonuses, \bar {x}_2 received by employees from company B

The standard deviation, σ₁, of the average annual bonuses for employees from company A

The standard deviation, σ₂, of the average annual bonuses for employees from company A

The number of employees in company A, n₁

The number of employees in company B, n₂

2. The null hypothesis is H₀: \bar {x}_1 - \bar {x}_2 ≤ 100

The alternative hypothesis is Hₐ: \bar {x}_1 - \bar {x}_2 > 100

Step-by-step explanation:

1. The required information are

The average annual bonuses, \bar {x}_1 received by employees from company A

The average annual bonuses, \bar {x}_2 received by employees from company B

The standard deviation, σ₁, of the average annual bonuses for employees from company A

The standard deviation, σ₂, of the average annual bonuses for employees from company A

The number of employees in company A, n₁

The number of employees in company B, n₂

2. The null hypothesis is H₀: \bar {x}_1 - \bar {x}_2 ≤ 100

The alternative hypothesis is Hₐ: \bar {x}_1 - \bar {x}_2 > 100

The z value for the hypothesis testing of the difference between two means is given as follows;

z=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\frac{\sigma_{1}^{2} }{n_{1}}-\frac{\sigma _{2}^{2}}{n_{2}}}}

At 0.5 level of significance, the critical z_\alpha = ± 0

The rejection region is z > z_\alpha and z < -z_\alpha

Therefore, the value of z obtained from the relation above more than or less than 0, we reject the null hypothesis, and we fail to reject the alternative hypothesis.

7 0
3 years ago
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