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Andreyy89
3 years ago
11

Factor by completing the square 5x^2-21=10x

Mathematics
1 answer:
velikii [3]3 years ago
4 0
Solve for x over the real numbers:
5 x^2 - 21 = 10 x

Subtract 10 x from both sides:
5 x^2 - 10 x - 21 = 0

Divide both sides by 5:
x^2 - 2 x - 21/5 = 0

Add 21/5 to both sides:
x^2 - 2 x = 21/5

Add 1 to both sides:
x^2 - 2 x + 1 = 26/5

Write the left hand side as a square:
(x - 1)^2 = 26/5

Take the square root of both sides:
x - 1 = sqrt(26/5) or x - 1 = -sqrt(26/5)

Add 1 to both sides:
x = 1 + sqrt(26/5) or x - 1 = -sqrt(26/5)

Add 1 to both sides:
Answer:  x = 1 + sqrt(26/5) or x = 1 - sqrt(26/5)
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Determine the equation of the line, written in slope-intercept form, that passes through the points (1,1) and (5,−1).
bazaltina [42]

Answer:

y=-1/2x+3/2

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-1-1)/(5-1)

m=-2/4

m=-1/2

y-y1=m(x-x1)

y-1=-1/2(x-1)

y=-1/2x+1/2+1

y=-1/2x+1/2+2/2

y=-1/2x+3/2

3 0
3 years ago
On a coordinate plane, a curved line labeled f of x with a minimum value of (1.9, negative 5.7) and a maximum value of (0, 2), c
77julia77 [94]

The graphed function, F(x), has a value greater than 0 over the intervals (-0.7, 0.76) and (0.76,  ∞) . F(x) > 0 over the intervals (-0.7, 0.76) and (0.76, ∞) is the correct statement [Fourth choice].

About a Graphed Function

The function graph of an object F stands for the set of all points in the plane that are (x, f(x)). The graph of f is also known as the graph of y = f. (x). The graph of an equation is thus a specific example of the graph of a function. A graphed function is a function that has been drawn out on a graph.

It is evident from the attached graph that the supplied function exceeds 0 for the following range:

-0.7 < F(x) < 0.76

And, 0.76 < F(x) < ∞

As a result, the intervals for which the given graphed function, F(x) is greater than 0 are as follows,

(-0.7, 0.76) and (0.76, ∞)

Learn more about a graphed function here:

brainly.com/question/27757761

#SPJ1

3 0
2 years ago
Alberta Doan worked 6 hours at time-and-a-half pay and 3 ¼ hours at double-time pay. Her regular pay rate was $9.72 an hour. Wha
natka813 [3]

Answer:

Alberta's total overtime pay of the week was $ 145.80.

Step-by-step explanation:

Given that Alberta worked 6 hours at time-and-a-half pay, and 3 hours at double-time pay, and that the value of her regular work hour is $ 9.72, to determine the value of the pay of his overtime, the following equation must be performed:

6x1.5x9.72 + 3x2x9.72 = X

9x9.72 + 6x9.72 = X

87.48 + 58.32 = X

145.8 = X

Therefore, Alberta's total overtime pay of the week was $ 145.80.

3 0
3 years ago
A=20 cm<br> b=48 cm<br> What is the length of c?
Ainat [17]
The value of c is 52
8 0
3 years ago
A line has slope -3/4and passes through the point (8, 3). Write an equation<br> of the line.
Phoenix [80]

Answer:

y=-3/4x + 0.25

Step-by-step explanation:

7 0
3 years ago
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